Question

下面是我想要转换为HQL的sql。有人可以帮我这个吗？我也发布了我的HQL，目前正在给我一个nullpointer异常 -

   select ti.tax_id_no,
   u1.user_id,
   u1.user_nm_fst,
   u1.user_nm_lst,
   u1.user_ph_no,
   u1.user_email
   from pcmp.tax_identifier ti
   inner join (select ucax.user_id, ucax.cust_id
           from pcmp.users_customer_access_xref ucax
          where ucax.ptcp_typ_cd = 'insrd'
            and ucax.void_ind = 'n'
            and ucax.user_cust_accs_xref_end_dt is null) ucax1
on ucax1.cust_id = ti.cust_id
inner join (select u.user_id,
                u.user_nm_fst,
                u.user_nm_lst,
                u.user_ph_no,
                u.user_email
           from pcmp.users u
          where u.user_end_dt is null
            and u.user_void_ind = 'n') u1
on u1.user_id = ucax1.user_id
where ti.tax_id_no = '830204947'-- '465202523'
and ti.void_ind = 'n'
and ti.tax_id_end_dt is null

我尝试使用以下查询但遇到了错误 -

        String queryString = "select u from User u"
                + " INNER JOIN u.ucax userCustomerAccessXref"                   
                + " INNER JOIN u.ti taxIdentifier"
                + " where taxIdentifier.tax_id_id = ?1";

我使用上述查询的例外是 -

显示java.lang.NullPointerException

org.hibernate.hql.ast.HqlSqlWalker.createFromJoinElement(HqlSqlWalker.java:383)
org.hibernate.hql.antlr.HqlSqlBaseWalker.joinElement(HqlSqlBaseWalker.java:3585)
org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElement(HqlSqlBaseWalker.java:3366)
org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElementList(HqlSqlBaseWalker.java:3239)
org.hibernate.hql.antlr.HqlSqlBaseWalker.fromClause(HqlSqlBaseWalker.java:726)

Answer 1

告诉我们您正在运行哪个版本的hibernate。可能有助于说明您的问题尽可能可重复用于其他人。对于那些不在你的业务领域的人来说，你的内心联系似乎非常复杂......

每当你通过连接字符串来启动查询时...对我而言，这表明你失去了对业务领域的控制权，因为你没有选择指定外部化的jpa / hibernate查询的方式。

HQL中的多个内部联接

1 个答案: