Question

标题说明了问题。

#include<stdio.h>
#include<conio.h>
main(){
char order, coffee, size, affirm;
float price;
clrscr();
printf("Hello, welcome to C Coffee Shop. How may I help you?\n");
printf(">Buy = B\n>Nothing = N\n"); /* Choose action */
scanf("%c",&order);
if(order == 'B'){ /* Decided to buy coffee */
  printf("What coffee would you want for today?\n"); /* Decide coffee type */
  printf(">Espresso = E\n>Americano = A\n>Latte = L\n");
  scanf("%c",&coffee);
  printf("How large would your drink be?\n"); /* Decide coffee size */
  printf(">Petite = P\n>Regular = R\n>Tall = T\n");
  scanf("%c",&size);
  if((coffee == 'E') && (size == 'P')){ /* Petite Espresso */
    price = 35;
    }
  else if((coffee == 'E') && (size == 'R')){ /* Regular Espresso */
    price = 50;
    }
  else if((coffee == 'E') && (size == 'T')){ /* Tall Espresso */
    price = 75;
    }
  else if((coffee == 'A') && (size == 'P')){ /* Petite Americano */ 
    price = 45;
    }
  else if((coffee == 'A') && (size == 'R')){ /*Regular Americano */
    price = 65;
    }
  else if((coffee == 'A') && (size == 'T')){ /* Tall Americano */
    price = 90;
    }
  else if((coffee == 'L') && (size == 'P')){ /* Petite Latte */
    price = 60;
    }
  else if((coffee == 'L') && (size == 'R')){ /* Regular Latte */
    price = 85;
    }
  else if((coffee == 'L') && (size == 'T')){ /* Tall Latte */
    price = 110;
    }
  printf("To clarify, your order is %c %c.\nThat would be %0.2f pesos.\n", size, coffee, price); /* Verify order */
  printf(">OK = O\n"); /* Affirm */
  scanf("%c",&affirm);
  if(affirm == 'O'){ /* Accept order */
    printf("Processing order...\n");
    }
  else{ /* Discard order */
    printf("Discarding order...\n");
    }
  printf("Thank you! Please come again.");
  }
else if(order == 'N'){ /* Decided not to buy coffee */
  printf("Thank you! Please come again.");
  }
getche();
return 0;
}

当我尝试运行程序时，第11-16行显示没有中断，禁止我执行其他命令。我认为这是我对scanf（）或if-else语句的误用。我不知道如何解决它。请帮帮忙？

if(order == 'B'){
  printf("What coffee would you want for today?\n");
  printf(">Espresso = E\n>Americano = A\n>Latte = L\n");
  scanf("%c",&coffee);
  printf("How large would your drink be?\n");
  printf(">Petite = P\n>Regular = R\n>Tall = T\n");
  scanf("%c",&size);

如果我的代码中有任何其他错误，请告诉我。 Tysm给那些有帮助的人：＆gt;

Answer 1

只要您有字符输入，例如

scanf("%c",&coffee);

在格式规范前加一个空格，比如

scanf(" %c",&coffee);

这将导致输入缓冲区中留下的任何前一个空格（例如前一个输入后的newline）被跳过，而不是被char读取。

Answer 2

当您在每个输入字符后按Enter键时，新行将被计为输入字符。这意味着你必须避免这些新的行字符。您可以通过以下方式执行此操作：

每次扫描后包含maven-antrun-plugin。
或者，将scanf重写为getchar()。

这样可以避免将新行字符计算为输入。

我的程序中的scanfs和/或ifs有问题（咖啡店）

2 个答案: