Question

我正在尝试根据匹配键获取jsonb结果。我有DB表“listing”，包含数字和数据列。

    number | data  
      1    |  {"name": "XYZ company", "city": "toronto", "province": "ON", "people" : [
{ "firstName": "tom", "lastName": "hanks", 
   "phonenumber": [{"type": "mobile", "Number": "111111"}], 
    "Email": [{"type": "business", "address": "tom@xyz.com"},{"type": "personal", "address": "tom@mailinator.com"}] }, 

{ "firstName": "sandra", "lastName": "petes", 
   "phonenumber": [{"type": "mobile", "Number": "333"}, {"type": "home", "Number": "444"}], 
    "Email": [{"type": "business", "address": "sandra@xyz.com"}] 
}
]}

我需要使用键 -

来提取数据列的所有值

以人为＆GT;姓名
以人为＆GT; lastName的
以人为＆GT; phonenumber-＆GT;编号
以人为＆GT;的电子邮件 - ＆gt;地址

到目前为止我所取得的成就是：

SELECT   number 
        ,jonb_array_length(jsonb_extract_path(data,'people')) as people_count
        ,jsonb_extract_path(data,'people','0','firstname') as FirstName
        ,jsonb_extract_path(data,'people','0','lastname') as LastName
        ,jsonb_extract_path(data,'people','0','email','Address'") as personEmail
        ,jsonb_extract_path(data,'people','0','phonenumber','Number') as personPhone
FROM    listings
WHERE   number='1';

然而，这只给了我第0个元素，我需要找到所有元素。有没有办法在单个查询中实现这一点。

谢谢你的时间！

Answer 1

您需要使用self函数来获取数组的所有元素。由于该函数返回一组行，因此您需要将其用作行源。

jsonb_array_elements()

这将导致SELECT '1' AS number, jsonb_array_length(data->'people') AS people_count, people->>'firstname' AS FirstName, people->>'lastname' AS LastName, people->'email'->0->>'Address' AS personEmail, people->'phonenumber'->0->>'Number' as personPhone FROM listings, jsonb_array_elements(data->'people') p(people) WHERE number = '1';的每个人都排成一行。电子邮件和电话号码对象也是数组，我在这里只选择第一个值。如果你想要所有这些，你只需要获取整个JSON数组，然后将它包装在外部查询中再次number = '1'。

postgres + jsonb +从multidimentional数组中获取key的值

1 个答案: