Question

您能告诉我如何使用Underscore.js查找首次出现的属性（无需完全匹配）吗？

我试过了。但是它只返回完全匹配的属性。让我们在我的列表中说```{r setup, include=FALSE} knitr::opts_chunk$set(echo = TRUE) library(Rramas) library(grDevices) library(devtools) ```就像townName一样。但我也需要选择Rocky Point。那我怎么能这样做呢？

Rocky

e.g。

var schoolDistrict = _.find(vm.schoolDistricts, function (d) { return d.townName 
== result.data[0].PropertyData.School; });

Answer 1

OP的反馈：我使用如下所示并正常工作：）

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="wrapper">

<span>span1</span>
<div class="el">div1</div>
<p class="big">paragraph A</p>
<p class="small">paragraph A</p>
</div>

另一种方式：

如果任一字符串是另一个字符串的子字符串，您可以进行原始检查。您还可以将字符串设置为小写以便更好地搜索：

var schoolDistrict = _.find(vm.schoolDistricts, function (s) { return 
s.townName.toLowerCase().indexOf(result.data[0].PropertyData.School.toLowerCase(
)) !== -1; });

var schoolDistricts = [
  {townName:'Rocky Point'}, 
  {townName: 'Roc'}
];

var searchString = 'Rocky'.toLowerCase();

var res = _.find(schoolDistricts, function(s) {
  var townName = s.townName.toLowerCase();
  return townName.indexOf(searchString) !== -1 || searchString.indexOf(townName) !== -1; 
});

console.log(res);

Answer 2

使用RegExp模式测试名称是否包含文本，并使用i标志忽略大小写：

var schoolDistricts = [{
  townName: 'South Rock'
}, {
  townName: 'Red Herring'
}, {
  townName: 'Rocky Point'
}, {
  townName: 'Whatnot'
}];

var school = 'Rocky'; // replacement for result.data[0].PropertyData.School

var pattern = new RegExp(school, 'i');

var result = _.find(schoolDistricts, function(d) {
  return pattern.test(d.townName);
});

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore-min.js"></script>

找出第一次出现的属性（不需要完全匹配）

2 个答案: