Question

我正在尝试使用Firebase从服务器向应用发送推送通知，但是当通知到达应用时，我的应用就崩溃了。

PHP代码：

       <?php

       $registrationIds = array("USER-DEVICE-TOKEN" );

       $message = array
       (
        'message'   => 'My awesome message',
        'title'     => 'My awesome title',
        'subtitle'  => 'My awesome subtitle',
        'tickerText'    => 'My awesome Ticker text',
        'vibrate'   => 1,
        'sound'     => 1,
        'largeIcon' => 'large_icon',
        'smallIcon' => 'small_icon'
       );


       $url = 'https://fcm.googleapis.com/fcm/send';
       $fields = array(
         'registration_ids' => $registrationIds,
         'data' => $message
        );
       $headers = array(
        'Authorization:key = GOOGLE-API-KEY',
        'Content-Type: application/json'
        );
       $ch = curl_init();
       curl_setopt($ch, CURLOPT_URL, $url);
       curl_setopt($ch, CURLOPT_POST, true);
       curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
       curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
       curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, 0);  
       curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
       curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode($fields));
       $result = curl_exec($ch);           
       if ($result === FALSE) {
           die('Curl failed: ' . curl_error($ch));
       }
       curl_close($ch);

       echo $result;

Output of PHP Script

我的Firebase消息服务：

public class MyFirebaseMessagingService extends FirebaseMessagingService {

private static final String TAG = "MyFirebaseMsgService";

@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
    //Displaying data in log
    //It is optional
    Log.d(TAG, "From: " + remoteMessage.getFrom());
    Log.d(TAG, "Notification Message Body: " + remoteMessage.getNotification().getBody()); // LINE 24
    //Calling method to generate notification
    sendNotification(remoteMessage.getNotification().getBody(),remoteMessage.getNotification().getTitle());
}

//This method is only generating push notification
//It is same as we did in earlier posts
private void sendNotification(String messageBody,String messageTitle) {
    Intent intent = new Intent(this, LoginActivity.class);
    intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
    PendingIntent pendingIntent = PendingIntent.getActivity(this, 0, intent,
            PendingIntent.FLAG_ONE_SHOT);

    Uri defaultSoundUri= RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
    NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(this)
            .setSmallIcon(R.drawable.mainlogo)
            .setContentTitle(messageTitle)
            .setContentText(messageBody)
            .setAutoCancel(true)
            .setSound(defaultSoundUri)
            .setContentIntent(pendingIntent);

    NotificationManager notificationManager =
            (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);

    notificationManager.notify(0, notificationBuilder.build());
}
       }

Crashing error when push notification comes

希望得到你的帮助

Answer 1

检查remoteMessage.getNotification()是否不为NULL。我认为它是NULL，因为您没有在PHP代码的$fields数组中发送参数'notification'。您正在发送“数据”。因此，当您发送参数'data'时，您必须使用remoteMessage.getData()获取该参数。

尝试在onMessageReceived方法中打印remoteMessage.getData().toString()的内容。它应该打印您在通知中发送的数据。

希望这有帮助。

如何使用Firebase将推送通知从服务器发送到应用程序？

1 个答案: