Question

我不确定time_diff方法中的内部SQL：

SELECT t1.started_at as chain_break,
time_to_sec(timediff(t1.started_at,IFNULL(
                                          (SELECT MAX(t2.ended_at)
                                           FROM status_records t2
                                           WHERE t2.user_id=189
                                           AND t2.started_at< t1.started_at
                                          ), t1.started_at
                                        )
                        )
                ) / 3600 AS time_off 
FROM status_records t1 
WHERE t1.user_id=189 
ORDER BY t1.ended_at DESC 
LIMIT 6

除了将此查询作为原始SQL放在DB::query中之外，还有一种很好的方法吗？

Answer 1

是的，您可以使用selectRaw()将子查询添加为字段选择。要创建子查询，可以创建另一个查询构建器。

Answer 2

试试这个

DB::raw("SELECT t1.started_at as chain_break,
time_to_sec(timediff(t1.started_at,IFNULL(
                                          (SELECT MAX(t2.ended_at)
                                           FROM status_records t2
                                           WHERE t2.user_id=189
                                           AND t2.started_at< t1.started_at
                                          ), t1.started_at
                                        )
                        )
                ) / 3600 AS time_off 
FROM status_records t1 
WHERE t1.user_id=189 
ORDER BY t1.ended_at DESC 
LIMIT 6");

如何将此查询转换为Laravel Query Builder？

2 个答案: