Question

我有三个名为用户，个人资料，分支和另外一个用于链接这三个表的表，userprofilebranch表。我的问题是

分支表是一个主表，我从中获取一些细节并将分支分配给用户，其中分支ID是PK。
与分支相同我有一个配置文件主表我在配置文件ID为PK时执行相同的操作。
我在保存用户时有一个用户表我希望在userprofilebranch表中保留branchid，profileid和userid。

User.java

 public class User implements Serializable, UserDetails {
    private static final long serialVersionUID = 1L;

    @Id
    @Column(name="USER_ID", nullable=false)
    @GeneratedValue(strategy=GenerationType.IDENTITY)
    private Long userId ;

    @Column(name="USERNAME")
    private String userName ;

    @Column(name="FIRST_NAME")
    private String firstName ;

    @Column(name="LAST_NAME")
    private String lastName ;



    @OneToOne(optional=true, mappedBy="mappedUser")
    private UserProfileBranch mappedUserProfileBranch;
    public User() {
        super();
    }

    public void setUserId( Long userId ) {
        this.userId = userId ;
    }
    public Long getUserId() {
        return this.userId;
    }

    public void setFirstName( String firstName ) {
        this.firstName = firstName;
    }
    public String getFirstName() {
        return this.firstName;
    }

    public void setLastName( String lastName ) {
        this.lastName = lastName;
    }
    public String getLastName() {
        return this.lastName;
    }
}

UserProfileBranch.java

 public class UserProfileBranch {

 @EmbeddedId @AttributeOverrides({
        @AttributeOverride(name="userId", column=@Column(name="USER_ID")),
        @AttributeOverride(name="branchCode", column=@Column(name="BRANCH_CODE")),
        @AttributeOverride(name="profileId", column=@Column(name="PROFILE_ID"))
    })
    private UserProfileBranchComposite userProfileBranchCompositeKey;



    @OneToOne(optional=true,fetch= FetchType.LAZY) @PrimaryKeyJoinColumns({
        @PrimaryKeyJoinColumn(name="USER_ID", referencedColumnName="USER_ID"), 
        @PrimaryKeyJoinColumn(name="BRANCH_CODE", referencedColumnName="BRANCH_CODE"),
        @PrimaryKeyJoinColumn(name="PROFILE_ID", referencedColumnName="PROFILE_ID")
    })
    private User mappedUser;


   public UserProfileBranchComposite getUserProfileBranchCompositeKey() {
    return userProfileBranchCompositeKey;
  }

   public void setUserProfileBranchCompositeKey(
        UserProfileBranchComposite userProfileBranchCompositeKey) {
    this.userProfileBranchCompositeKey = userProfileBranchCompositeKey;
}
}

UserProfileBranchCompositeKey

@Embeddable
public class UserProfileBranchComposite implements Serializable{


/**
 * 
 */
private static final long serialVersionUID = 1L;

@Column(name="USER_ID",nullable= false)
private Long userId;



@Column(name="BRANCH_CODE",nullable= false)
private String branchCode;

@Column(name="PROFILE_ID")
private String profileId;

public UserProfileBranchComposite() {

}

public UserProfileBranchComposite(Long userId) {
    this.userId = userId;
}

public Long getUserId() {
    return userId;
}

public void setUserId(Long userId) {
    this.userId = userId;
}


public String getBranchCode() {
    return branchCode;
}

public void setBranchCode(String branchCode) {
    this.branchCode = branchCode;
}

public String getProfileId() {
    return profileId;
}

public void setProfileId(String profileId) {
    this.profileId = profileId;
}
}

当我执行代码时出现此错误

引起：org.hibernate.MappingException：已损坏的列映射：mappedUser.id：in.vit.leasing.security.domain.model.UserProfileBranch 在org.hibernate.persister.entity.AbstractPropertyMapping.initPropertyPaths（AbstractPropertyMapping.java:178）在org.hibernate.persister.entity.AbstractPropertyMapping.initIdentifierPropertyPaths（AbstractPropertyMapping.java:242）在org.hibernate.persister.entity.AbstractPropertyMapping.initPropertyPaths（AbstractPropertyMapping.java:222）在org.hibernate.persister.entity.AbstractEntityPersister.initOrdinaryPropertyPaths（AbstractEntityPersister.java:2457）在org.hibernate.persister.entity.AbstractEntityPersister.initPropertyPaths（AbstractEntityPersister.java:2494）在org.hibernate.persister.entity.AbstractEntityPersister.postConstruct（AbstractEntityPersister.java:3949）在org.hibernate.persister.entity.SingleTableEntityPersister。（SingleTableEntityPersister.java:453） at sun.reflect.NativeConstructorAccessorImpl.newInstance0（Native Method） at sun.reflect.NativeConstructorAccessorImpl.newInstance（NativeConstructorAccessorImpl.java:62） at sun.reflect.DelegatingConstructorAccessorImpl.newInstance（DelegatingConstructorAccessorImpl.java:45） at java.lang.reflect.Constructor.newInstance（Constructor.java:422）在org.hibernate.persister.internal.PersisterFactoryImpl.create（PersisterFactoryImpl.java:163）在org.hibernate.persister.internal.PersisterFactoryImpl.createEntityPersister（PersisterFactoryImpl.java:135）在org.hibernate.internal.SessionFactoryImpl。（SessionFactoryImpl.java:401）在org.hibernate.cfg.Configuration.buildSessionFactory（Configuration.java:1859）在org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl $ 4.perform（EntityManagerFactoryBuilderImpl.java:857）

我duno在哪里我错了。有人可以帮我解决这个问题

Answer 1

我的个人经验建议：不要在Hibernate中使用复合键，使用生成的主键。优点：

更简单的映射，减少头痛
减少存储空间（一列用于存储外键，而不是三列）
更好的表现

如果你想要它很难：尝试将所有者更改为User.java：

@OneToOne(optional=true)
@JoinColumns({
    @JoinColumn(name="KEY_USER_ID", referencedColumnName="USER_ID", updateable=false, insertable=false),
    @JoinColumn(name="KEY_BRANCH_CODE", referencedColumnName="BRANCH_CODE", updateable=false, insertable=false),
    @JoinColumn(name="KEY_PROFILE_ID", referencedColumnName="PROFILE_ID", updateable=false, insertable=false)
})
private UserProfileBranch mappedUserProfileBranch;

jpa中id的一对一断列映射？

1 个答案: