我将是第一个承认,我是100%的C#家伙而C不适合我。但是我有问题。 我需要将7与HashUrl(HashInt)连接,然后与HashInt连接 任何帮助将不胜感激。
int main(int argc)
{
unsigned int HashInt;
HashInt = HashURL(argc);
// I need to return 7 + CheckHash(HashInt) + HashInt but not ADDING, but concanenating them
return HOWEVERTOGETTHESTRING;
}
我应该已经指定了这个用法。它实际上将用于学生VB6项目。
Private Declare Function main Lib "checksum.dll" (ByVal pStr As String) As Long
Private Sub Command1_Click()
MsgBox main("http://hello.com")
End Sub
C库的完整源代码是
#include <stdio.h>
#include <string.h>
#include <windows.h>
#include <string.h>
#include <winreg.h>
#include <stdlib.h>
int StrToInt(char *pStr, int Init, int Factor)
{
while (*pStr) {
Init *= Factor;
Init += *pStr++;
}
return Init;
}
int HashURL(char *pStr)
{
unsigned int C1, C2, T1, T2;
C1 = StrToInt(pStr, 0x1505, 0x21);
C2 = StrToInt(pStr, 0, 0x1003F);
C1 >>= 2;
C1 = ((C1 >> 4) & 0x3FFFFC0) | (C1 & 0x3F);
C1 = ((C1 >> 4) & 0x3FFC00) | (C1 & 0x3FF);
C1 = ((C1 >> 4) & 0x3C000) | (C1 & 0x3FFF);
T1 = (C1 & 0x3C0) << 4;
T1 |= C1 & 0x3C;
T1 = (T1 << 2) | (C2 & 0xF0F);
T2 = (C1 & 0xFFFFC000) << 4;
T2 |= C1 & 0x3C00;
T2 = (T2 << 0xA) | (C2 & 0xF0F0000);
return (T1 | T2);
}
char CheckHash(unsigned int HashInt)
{
int Check = 0, Flag = 0;
int Remainder;
do {
Remainder = HashInt % 10;
HashInt /= 10;
if (1 == (Flag % 2) ){
Remainder += Remainder;
Remainder = (Remainder / 10) + (Remainder % 10);
}
Check += Remainder;
Flag ++;
} while( 0 != HashInt);
Check %= 10;
if (0 != Check) {
Check = 10 - Check;
if (1 == (Flag % 2)) {
if (1 == (Check % 2)) {
Check += 9;
}
Check >>= 1;
}
}
Check += 0x30;
return Check;
}
int main(int argc)
{
unsigned int HashInt;
int result;
HashInt = HashURL(argc);
char temp[100];
sprintf(temp, "7%i%j", CheckHash(HashInt), HashInt);
result = atoi(temp);
return result;
}
给“http://www.hello.com”应返回783544359868,但不是
答案 0 :(得分:5)
您可以使用sprintf函数创建格式化字符串。要将3个整数连接成一个字符串,您可以使用类似
的内容sprintf(string, "%d%d%d", int1, int2, int3)
答案 1 :(得分:1)
我在C上并不是那么出色,但我如何解决这个问题的方法是首先将它们转换为字符数组,然后将它们连接起来。然后你可以把结果变回int:
int main(int argc) {
unsigned int HashInt;
int result;
HashInt = HashURL(argc);
char temp[50];
sprintf(temp, "7%i%i", CheckHash(HashInt), HashInt);
result = atoi(temp);
return result;
}
注意:这项工作无法保证...
答案 2 :(得分:0)
对于初学者,你可以看一下:
asprintf
在Linux系统上做man asprintf
。
这是一个链接,它有一个简单的例子,你可以适应:
http://www.gnu.org/s/libc/manual/html_node/Dynamic-Output.html