Question

此代码按执行顺序排列的重要事项：

1.打开并阅读文件＆＃34;商品＆＃34;

2.从文件中选择一个随机行＆＃34; Goods＆＃34;到字典＆＃34;货物＆＃34;

3.通过if块，将随机值分配给字典＆＃34; cost＆＃34;如果goods [x]等于它被比较的字符串。

4.Print＆＃34; goods＆＃34;，＆＃34; cost＆＃34;

5.重复步骤2-4,2次。

from random import randint

print("You search for things to buy in the market, and find:")
f = open('Goods', 'r') #Opens file "Goods"
lines = f.readlines() #Loads all lines from "Goods"
goods = {1:"", 2:"", 3:""}
cost = {1:"", 2:"", 3:""}
x = 0
while x < 3:
    x += 1
    goods[x] = lines[randint(0, 41)].strip()

#Checks to see if goods[x] is equal to the string on the right, if it is, it assigns cost[x] to a random integer
    if goods[x] == "Lumber":
        cost[x] = randint(2, 3)
    elif goods[x] == "Rum":
        cost[x] == randint(3, 4)
    elif goods[x] == "Spices":
        cost[x] = randint(4, 5)
    elif goods[x] == "Fruit":
        cost[x] == randint(2, 4)
    elif goods[x] == "Opium":
        cost[x] == randint(1, 5)


    findings = '%s for %s gold.' %(goods[x], cost[x])
    print(findings)

这段代码的问题在于字典：＆＃34; cost＆＃34;当货物[x]等于：朗姆酒，水果或鸦片时，不会从if块分配值。

有人可以告诉我这里发生了什么吗？

The file "Goods"

Answer 1

你的问题是你使用两个相同的标志。 cost[x] == randint(3, 4)您只需要使用一个。希望这有帮助！

将文件行与python中的字符串进行比较，以及不一致

1 个答案: