我有一个Bourne shell脚本，它使用End-of-Transmission字符作为IFS：
read EOT如何表现为IFS？或者var xml1 =
"<?xml version=\"1.0\" encoding=\"utf-8\"?><foo:NameHent xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:foo1=\"http://sample.com\" xmlns:foo=\"http://example.com\"><foo1:Firstname>John</foo1:Firstname><foo1:Firstname>Michael</foo1:Firstname><foo1:Lastname>Doe</foo1:Lastname><foo1:Date>1988-03-05</foo1:Date></foo:NameHent>";
XmlSerializer xmlSerializer = new XmlSerializer(typeof(NameHent));
NameHent c = xmlSerializer.Deserialize(new StringReader(xml1)) as NameHent;
public class NameHent
{
[XmlElement(Namespace = "http://sample.com")]
public string [] Firstname;
[XmlElement(Namespace = "http://sample.com")]
public string Lastname;
[XmlElement(Namespace = "http://sample.com")]
public string Date;
[XmlNamespaceDeclarations]
public XmlSerializerNamespaces xmlns = new XmlSerializerNamespaces();
public NameHent()
{
xmlns.Add("foo", "http://example.com");
xmlns.Add("foo1", "http://sample.com");
}
}
期望什么样的输入？
答案 0 :(得分：1)
它是一个ASCII字符，就像,一样;它只是不可打印。
$ printf 'foo\004bar' > tmp.txt
$ hexdump -C tmp.txt
00000000 66 6f 6f 04 62 61 72 0a |foo.bar.|
00000008
$ IFS=$(printf '\004') read f1 f2 < tmp.txt
$ echo "$f1"
foo
$ echo "$f2"
bar