Question

我有一个简单的AJAX请求到PHP文件。一旦PHP脚本到达某一点，我希望响应完成并发送回客户端。之后我仍然需要PHP脚本来运行一个最多需要15秒的函数。目前，浏览器在处理响应之前等待整个PHP脚本完成。我曾尝试使用flush();或ob_flush();，但在发送响应之前，它仍然等待PHP脚本完成运行。

JQuery代码：

jQuery.ajax({
            url: "../phpFile.php",
            data: formdata,
            cache: false,
            contentType: false,
            processData: false,
            type: 'POST',
            success: function (data) {
                data = $.parseJSON(data);
                if(data.success){
                    window.location = "../public/dashboard.php";
                }
           }
});

PHP代码：

if ($script_reached_this_point) {

    // ob_start();
    echo json_encode(['success' => 'Ticket added']);
    //flush();
    //  ob_end_flush();

    run_15_second_function();

}

Answer 1

我通过使用2个PHP脚本解决了类似的问题。我们称他们为receiver.php和worker.php。过程如下：

AJAX调用receiver.php
receiver.php在辅助连接中调用worker.php，向其传递作业说明并等待第一行响应。
一旦第一行回复从worker.php到达，receiver.php就会关闭该连接
receiver.php立即返回对AJAX的响应并退出。
worker.php继续在后台工作

<强> receiver.php

//data to be forwarded to worker.php
$postData = json_encode($_POST);

// headers for the connection to worker.php
$headers =  "POST /path/to/worker.php HTTP/1.1".PHP_EOL;
$headers .= "Host: localhost".PHP_EOL;
$headers .= "Content-Length: ".strlen($postData).PHP_EOL;
$headers .= "Content-Encoding: none".PHP_EOL;
$headers .= "Content-Type: application/json".PHP_EOL;

// create socket to the local webserver for calling background script
$socketToWorker = fsockopen("localhost", 80, $errno, $err_msg);
if(!$socketToWorker) die("fsockopen error #$errno: $err_msg");

// Make the request and send the POST data
fwrite($socketToWorker, $headers.PHP_EOL.$postData);    

//read until the 1st packet is returned, then stop. 8192 is arbitrary
//but needs to be greater than the expected response from worker.php
$data = fread($socketToWorker,8192);
fclose($socketToWorker);

//send response to browser (work still ongoing in background)
if($data==='OK') echo "Success";
else echo "Background work failed. Error: $data";

<强> worker.php

//parse input from receiver.php
$postData = json_decode(file_get_contents('php://input'),true);

//TODO: validate $postData. 

// If data is valid, set below to 'OK' to accept the job
$acceptJob = 'OK'; //replace with an error message to reject the job
ob_start(); //start the buffer
echo $acceptJob; //this is what receiver.php will see

//set headers for the response to receiver.php
header("Content-Encoding: none");
header('Connection: close');
header('Content-Length: '.ob_get_length() );

// flush buffer. Will cause receiver.php to receive data and disconnect
ob_end_flush(); ob_flush(); flush();

if($acceptJob!=='OK') exit;

##################### START THE JOB HERE #####################
set_time_limit(60); //only needed if you expect job to last more than 30 secs
run_15_second_function();

在脚本完成之前返回从php到ajax的响应

1 个答案: