Question

拥有以下数据：

declare @test_names TABLE(id int identity(1,1), name character varying(50),age int);
INSERT INTO @test_names(name,age) values ('name1',10),('name2',20);

declare @test_names_details TABLE(id int identity(1,1), test_names_id int,col1 int,col2 int,col3 int);

INSERT INTO @test_names_details(test_names_id,col1,col2,col3)
VALUES(1,2,3,4),(1,5,6,7),(1,8,9,10),(2,20,21,22),(2,23,24,25);

想要从第二个表中选择第一个表值的详细信息。怎么做？输出必须如下：

field1     field2   field3
name1        10      
2            3       4
5            6       7
8            9       10
name2        20
20           21      22
23           24      25

被修改

在表格中我有很多行（name1，name2，name3 ..），例如我只写了两行

Answer 1

DECLARE @output TABLE(field1 VARCHAR(50), field2 VARCHAR(50), field3 VARCHAR(50))
DECLARE @test_names_count INT,
        @counter INT
SELECT @test_names_count = COUNT(1) FROM @test_names
SET @counter = 1

WHILE (@counter <= @test_names_count)
BEGIN
    INSERT INTO @output SELECT name, age, '' FROM @test_names WHERE id = @counter
    INSERT INTO @output SELECT col1, col2, col3 FROM @test_names_details WHERE test_names_id = @counter

    SET @counter = @counter + 1
END

SELECT * FROM @output

Answer 2

针对任意数量的名称列进行了更新：

基于设置的解决方案，将列名替换为您选择的名称

            Dim toString As String
            toString = cell.Value & "_"
               If (InStr(toString, ",")) Then
                 toString = Replace(toString, ",", ".")
                 toString = Trim(toString)
                 cell.Value = " " + Left(toString, (Len(toString) - 1))               
               End If

如何通过第一个表值获取第二个表值

2 个答案: