我正在尝试将我的NSDictionary分配给我的NSArray但应用程序每次崩溃都是我的代码:
NSDictionary *dict = [[NSDictionary alloc]init];
for (int i=0; i< myMutableArray.count; i++) {
dict = [NSDictionary dictionaryWithObjectsAndKeys:[[myMutableArray objectAtIndex:i]xmlhotel_name], @"hotelname",
[PriceArray objectAtIndex:i], @"startingfrom",
[[myMutableArray objectAtIndex:i]xmlhotel_city],@"city",
[DistanceArray objectAtIndex:i],@"distance",
[[myMutableArray objectAtIndex:i]xmlhotel_image],@"imagesnames",
[[myMutableArray objectAtIndex:i]xmlhotel_stars],@"numberofstars",
@"45.5016889",@"hotelLat",
@"-73.567256",@"hotelLong", nil];
}
NSArray *myArray = @[@{[dict allKeys] : [dict allValues]}];
这是我传递数据的时候
BookATableController = [self.storyboard instantiateViewControllerWithIdentifier:@"bookatable"];
BookATableController.myMutableArray=[[NSMutableArray alloc]initWithArray:self.rssOutputData];/// Passing Data
BookATableController.PriceArray=[[NSMutableArray alloc]initWithArray:rssHotelPrice];/// Passing Data
BookATableController.DistanceArray=[[NSMutableArray alloc]initWithArray:rssHotelDistance];/// Passing
[self.view addSubview:BookATableController.view];
[self addChildViewController:BookATableController];
[BookATableController didMoveToParentViewController:self];
答案 0 :(得分:1)
一个词典不起作用,因为当前状态的键不是唯一的。关于可能解决方案的两点建议,
1)我认为最好是使用您要存储的属性创建一个Hotel对象,并在for循环中初始化这些对象。如果你愿意,我可以给你一个例子。
2)如果您想使用字典,您可以执行下面我列出的操作,尽管您可以尝试其他许多变体。
NSMutableArray *arrayOfHotels = [[NSMutableArray alloc] init];
// 5 is random, you can use the count from 'myMutableArray'
for (int i=0; i < 5; i++) {
NSArray *columnNames = @[@"hotelname",
@"startingfrom",
@"city",
@"distance",
@"imagesnames",
@"numberofstars",
@"hotelLat",
@"hotelLong"];
NSArray *values = @[[[myMutableArray objectAtIndex:i]xmlhotel_name],
[PriceArray objectAtIndex:i],
[[myMutableArray objectAtIndex:i]xmlhotel_city],
[DistanceArray objectAtIndex:i],
[[myMutableArray objectAtIndex:i]xmlhotel_image],
[[myMutableArray objectAtIndex:i]xmlhotel_stars],
@"45.5016889",
@"-73.567256"];
[arrayOfHotels addObject:[NSDictionary dictionaryWithObjects:columnNames forKeys:values]];
}