我遇到谷歌脚本问题并将我的Google工作表保存为csv。我试图使用我在互联网上找到的代码将工作表转换为csv,但是当我运行它时,文件类型显示未知而不是csv。没有它将它保存到csv google工作表是没用的。这是我找到的在线代码。不是我的代码,但我一直试图使用的代码。
/*
* script to export data in all sheets in the current spreadsheet as individual csv files
* files will be named according to the name of the sheet
* author: Michael Derazon
*/
function onOpen() {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var csvMenuEntries = [{name: "export as csv files", functionName: "saveAsCSV"}];
ss.addMenu("csv", csvMenuEntries);
};
function saveAsCSV() {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheets = ss.getSheets();
// create a folder from the name of the spreadsheet
var folder = DriveApp.createFolder(ss.getName().toLowerCase().replace(/ /g,'_') + '_csv_');
for (var i = 0 ; i < sheets.length ; i++) {
var sheet = sheets[i];
// append ".csv" extension to the sheet name
fileName = sheet.getName() + ".csv";
// convert all available sheet data to csv format
var csvFile = convertRangeToCsvFile_(fileName, sheet);
// create a file in the Docs List with the given name and the csv data
folder.createFile(fileName, csvFile);
var files = folder.getFiles();
while (files.hasNext()){
var file = files.next();
var destination = DriveApp.getFolderById("0B21i2lCR63QPTGdrcE9rMFgtLVk");
destination.addFile(file);
/*
var pull = folder;
pull.removeFile(file);
*/
}
}
Browser.msgBox('Files are waiting in a folder named ' + folder.getName());
}
function convertRangeToCsvFile_(csvFileName, sheet) {
// get available data range in the spreadsheet
var activeRange = sheet.getDataRange();
try {
var data = activeRange.getValues();
var csvFile = undefined;
// loop through the data in the range and build a string with the csv data
if (data.length > 1) {
var csv = "";
for (var row = 0; row < data.length; row++) {
for (var col = 0; col < data[row].length; col++) {
if (data[row][col].toString().indexOf(",") != -1) {
data[row][col] = "\"" + data[row][col] + "\"";
}
}
// join each row's columns
// add a carriage return to end of each row, except for the last one
if (row < data.length-1) {
csv += data[row].join(",") + "\r\n";
}
else {
csv += data[row];
}
}
csvFile = csv;
}
return csvFile;
}
catch(err) {
Logger.log(err);
Browser.msgBox(err);
}
}
答案 0 :(得分:0)
我相信此链接可能会对您有所帮助:http://www.instructables.com/id/Export-data-from-google-spreadsheet-in-required-CS/ (如果您不能使用PHP,那么这里是下载链接:http://php.net/downloads.php)。我假设你不需要脚本在javascript中。
答案 1 :(得分:0)
我明白了。看起来我要做的就是将MimeType.CSV添加到createFile方法的末尾。现在它肯定将它保存为csv。
folder.createFile(fileName, csvFile,MimeType.CSV);