Question

我有一个Part列表，其中包含DateTime注册到Database时的@{ var shiftChangeTime = new TimeSpan(16, 0, 0); <table> <tr> @*This is my general average*@ <td>Number of part/hour</td> @{ var avg = Model.GroupBy(x => ((DateTime)x.ScanTime).TimeOfDay.Hours) .Average(x => x.Count()); <td>@(Math.Round(avg, 2))</td> } </tr> <tr> @*This is my day average*@ <td>Number of part/hour</td> @{ var avgDay = Model.GroupBy(x => ((DateTime)x.ScanTime).TimeOfDay < shiftChangeTime, y => ((DateTime)y.ScanTime).TimeOfDay.Hours) .Average(x => x.Count()); <td>@(Math.Round(avgDay, 2))</td> } </tr> <tr> @*This is my night average*@ <td>Number of part/hour for night shift</td> @{ var avgNight = Model.GroupBy(x => ((DateTime)x.ScanTime).TimeOfDay > shiftChangeTime, y => ((DateTime)y.ScanTime).TimeOfDay.Hours) .Average(x => x.Count()); <td>@(Math.Round(avgNight, 2))</td> } </tr> </table> }值。

我想显示每小时白班和每夜班次登记的人数。

我试图将我的普通平均值的逻辑基于这两个值

Declare @String varchar(max) = 'FinancialYear=47faabe1-f6aa-e411-941e-00155d010d10&FinancialPeriod=4dfaabe1-f6aa-e411-941e-00155d010d10&Branch=eefb631b-4e1b-e611-9436-00155d010d10&Branch=369d0919-edaa-e411-941e-00155d010d10&Branch=e9a7dc75-f9aa-e411-941e-00155d010d10&Branch=cb3a3c67-f9aa-e411-941e-00155d010d10&Department=00000000-0000-0000-0000-000000000000&Department=adb0f49a-4f1b-e611-9436-00155d010d10&Department=487c64ae-4f1b-e611-9436-00155d010d10&Department=4c9b0919-edaa-e411-941e-00155d010d10'
Select Seq   =Key_PS
      ,Item  =Substring(Key_Value,1,charindex('=',Key_Value)-1)
      ,Value =Substring(Key_Value,  charindex('=',Key_Value)+1,100)
 From [dbo].[udf-Str-Parse](@String,'&')

我目前坚持按小时划分昼/夜转换的逻辑。

现在它将我的总人数分成两部分。

关于如何进行的任何想法？

Answer 1

上述代码存在的问题是，在GroupBy天/夜班后，您还需要按Hour进行分组才能达到小时平均值。

这可以显示白天/夜班中一小时内的平均部分：

List<Part> Model = new List<Part>
{
    new Part{ ScanTime = new DateTime(2016,1,1,1,0,0) },
    new Part{ ScanTime = new DateTime(2016,1,1,4,0,0) },
    new Part{ ScanTime = new DateTime(2016,1,1,4,0,0) },
    new Part{ ScanTime = new DateTime(2016,1,1,4,0,0) },
    new Part{ ScanTime = new DateTime(2016,1,1,4,0,0) },
    new Part{ ScanTime = new DateTime(2016,1,1,7,0,0) },
    new Part{ ScanTime = new DateTime(2016,1,1,12, 0,0) },
    new Part{ ScanTime = new DateTime(2016,1,1,17,0,0) },
    new Part{ ScanTime = new DateTime(2016,1,1,19,0,0) },
    new Part{ ScanTime = new DateTime(2016,1,1,23,0,0) },
};

var shiftChangeTime = new TimeSpan(12, 0, 0);

var result = Model.GroupBy(x => x.ScanTime.TimeOfDay < shiftChangeTime ? "Day" : "Night")
     .Select(g => new
     {
         Shift = g.Key,
         Average = g.GroupBy(item => item.ScanTime.Hour, 
                             (key, group) => new { Hour = key, Amount = group.Count() })
                    .Average(y => y.Amount)
     }).ToList();

如果您不希望2 GroupBy，则另一个选项是首次使用Where来保留特定班次的记录，然后是其他选项：

var dayAverage = Model.Where(x => x.ScanTime.TimeOfDay < shiftChangeTime)
                      .GroupBy(item => item.ScanTime.Hour, 
                               (key, group) => new { Hour = key, Amount = group.Count() })
                      .Average(y => y.Amount);

使用LINQ显示每小时的平均时间

1 个答案: