在猪中旋转行

Question

我输入数据为：

Abhinav,10K
Abhinav,20K
Abhinav,30K
Nitin,15K
Nitin,25K
Mohit,50K

我需要最终输出为：

(Abhinav,10K,20K,30K)
(Nitin,15K,25K)
(Mohit,50K)

我来到这个中间点：

(Abhinav,{(10K),(20K),(30K)})
(Mohit,{(50K)})
(Nitin,{(15K),(25K)})

此外，有没有办法将此中间点转换为最终解决方案。

Answer 1

不知怎的，我得到了答案，这很容易！

 NameSal = LOAD '/home/asingh50/NameSalary.txt' USING PigStorage(',') AS(name:chararray,salary:chararray);
 NameSalGroup = GROUP NameSal by (name);
 NameSalResult = FOREACH NameSalGroup GENERATE group AS Name, BagToString(NameSal.salary, ',') as salary:chararray;