Question

中举例说明

#include <iostream>
#include <string>
#include <boost/program_options.hpp>

int main(int const ac, char** const av){

  // Declare the supported options.
  namespace po = boost::program_options;
  using namespace std;
  po::options_description desc("Allowed options");
  desc.add_options()
      ("help", "produce help message")
      ("compression", po::value<int>(), "set compression level")
  ;

  po::variables_map vm;
  po::store(po::parse_command_line(ac, av, desc), vm);
  po::notify(vm);    

  if (vm.count("help")) {
      cout << desc << "\n";
      return 1;
  }

  if (vm.count("compression")) {
      cout << "Compression level was set to " 
   << vm["compression"].as<int>() << ".\n";
  } else {
      cout << "Compression level was not set.\n";
  }
}

程序运行正常但是，当用gcc的消毒剂（或clang's）编译时：

g++ -std=c++1z -o main main.cpp -fsanitize=undefined -lboost_program_options

它产生以下运行时错误：

./main --compression="1"                                                                                                                                                          134
/usr/include/boost/any.hpp:243:16: runtime error: downcast of address 0x000001153fb0 which does not point to an object of type 'holder'
0x000001153fb0: note: object is of type 'boost::any::holder<int>'
 00 00 00 00  20 bc 42 00 00 00 00 00  01 00 00 00 00 00 00 00  00 00 00 00 00 00 00 00  31 00 00 00
              ^~~~~~~~~~~~~~~~~~~~~~~
              vptr for 'boost::any::holder<int>'
Compression level was set to 1.

我已将问题提炼为更小的问题：

#include <iostream>
#include <string>
#include <boost/program_options.hpp>

int main(int const argc, char** const argv){

  using namespace boost::program_options;

  //create description
  options_description desc("");

  //add entry
  desc.add_options()
  ("foo",value<std::string>(),"desc");

  //create variable map
  variables_map vm;

  //store variables in map
  positional_options_description pod;
    store(command_line_parser(argc, argv).options(desc).positional(pod).run(), vm);
    notify(vm);

    //get variable out of map
    std::string foo;
    if (vm.count("foo")){
        foo = vm["foo"].as<std::string>(); //UNDEFINED BEHAVIOUR
    }
}

编译：

g++ -std=c++1z -o main main.cpp -fsanitize=undefined -lboost_program_options

执行时：

./main --foo="hello"
/usr/include/boost/any.hpp:243:16: runtime error: downcast of address 0x000000d85fd0 which does not point to an object of type 'holder'
0x000000d85fd0: note: object is of type 'boost::any::holder<std::string>'
 00 00 00 00  b0 c5 5e 90 f8 7f 00 00  98 5f d8 00 00 00 00 00  00 00 00 00 00 00 00 00  31 00 00 00
              ^~~~~~~~~~~~~~~~~~~~~~~
              vptr for 'boost::any::holder<std::string>'

显然，它是导致UB的变量映射的强制转换：

vm["foo"].as<std::string>()

这正是在线文档显示的方式。

这是误报吗？我的增压分配中是否有错误？
如果它确实安全，我怎样才能避免清洁剂标记？

Answer 1

这似乎是一种不确定的行为。此代码说明了此问题：

#include <boost/any.hpp>

int main()
{
    int value = 0;
    int const& const_ref = value;
    boost::any any_var {const_ref};
    boost::any_cast<int&>(any_var); // ubsan error
}

这里any_var用const值构造，并作为非const int访问。使用清理程序运行此代码会引发与您的类似的运行时错误：

/usr/local/include/boost/any.hpp:259:16: runtime error: downcast of address 0x60200000eff0 which does not point to an object of type 'any::holder<int>'
0x60200000eff0: note: object is of type 'boost::any::holder<int const>'
 01 00 00 0c  b0 ee 49 00 00 00 00 00  00 00 00 00 be be be be  00 00 00 00 00 00 00 00  00 00 00 00
              ^~~~~~~~~~~~~~~~~~~~~~~
              vptr for 'boost::any::holder<int const>'
SUMMARY: AddressSanitizer: undefined-behavior /usr/local/include/boost/any.hpp:259:16 in 
/usr/local/include/boost/any.hpp:259:73: runtime error: member access within address 0x60200000eff0 which does not point to an object of type 'any::holder<int>'
0x60200000eff0: note: object is of type 'boost::any::holder<int const>'
 01 00 00 0c  b0 ee 49 00 00 00 00 00  00 00 00 00 be be be be  00 00 00 00 00 00 00 00  00 00 00 00
              ^~~~~~~~~~~~~~~~~~~~~~~
              vptr for 'boost::any::holder<int const>'
SUMMARY: AddressSanitizer: undefined-behavior /usr/local/include/boost/any.hpp:259:73 in

问题是代码中的any_cast<int&>尝试通过向下转换类型擦除指针any::holder<int>来访问存储值，但实际类型为any::holder<int const>。因此未定义的行为。

boost :: program_options

中的未定义行为

在boost :: program_options中，类型T的值存储为any类中的typed_value<T>对象。 any对象的构造如下：

// In class typed_value
typed_value* implicit_value(const T &v)
{
    m_implicit_value = boost::any(v);
    m_implicit_value_as_text =
        boost::lexical_cast<std::string>(v);
    return this;
}

请注意，值v被声明为const引用。但是，typed_value<T>::notify()（在代码中从po::notify()调用）访问存储的值而不使用const：

template<class T, class charT>
void
typed_value<T, charT>::notify(const boost::any& value_store) const
{
    const T* value = boost::any_cast<T>(&value_store);
    ...
}

这会导致未定义的行为。

解决方法

在boost / program_options / value_semantic.hpp中，更改implicit_value()函数的以下行

m_implicit_value = boost::any(v);

到

m_implicit_value = boost::any(T(v));

这使洗手液很开心。我不确定这是否真的可以解决。

为什么boost :: any在boost :: program_options中表现出未定义的行为？

1 个答案:

boost :: program_options

解决方法