获取Android计时器

时间:2016-08-16 21:37:21

标签: android timer android-edittext

我有一个简单的Timer,它可以使用onTick方法。我有几个分钟和秒的TextBox,但是当其中一个是空的时它崩溃了。我该如何管理这两个TextBox? 这是我的启动计时器按钮的onClick方法中的代码。

 @Override
public void onClick(View view) {
    switch (view.getId()) {
        case R.id.startTimer:
            //If CountDownTimer is null then start timer
            if (countDownTimer == null) {
                String getMinutes = minutes.getText().toString();//Get minutes from Minutes EditText
                String getSeconds = seconds.getText().toString();//Get seconds from Seconds EditText
                //Check validation over EditText
                if ((!getMinutes.equals("") && getMinutes.length() > 0)) {
                    int noOfMinutes = Integer.parseInt(getMinutes) * 60 * 1000;//Convert minutes into milliseconds
                    int noOfSeconds=Integer.parseInt(getSeconds) * 1000;//Convert Seconds into milliseconds

                    time = noOfMinutes + noOfSeconds;
                    startTimer(time);//start countdown
                    startTimer.setText(getString(R.string.stop_timer));//Change Text

                } else
                    Toast.makeText(MainActivity.this, "Please enter no. of Minutes.", Toast.LENGTH_SHORT).show();//Display toast if Minute EditText is empty
            } else {
                //else stop timer and change text
                stopCountdown();
                startTimer.setText(getString(R.string.start_timer));
            }
            break;
        case R.id.resetTimer:
            stopCountdown();//stop count down
            startTimer.setText(getString(R.string.start_timer));//Change text to Start Timer
            countdownTimerText.setText(getString(R.string.timer));//Change Timer text
            break;
    }
}

当getSeconds EdidtTex为空时,Log Cat中出现此错误:

错误:

08-17 07:48:26.402 3789-3789 / amir.app.pro.my_timer2 E / AndroidRuntime:FATAL EXCEPTION:main                                                                       java.lang.NumberFormatException:无效的int:“”                                                                           在java.lang.Integer.invalidInt(Integer.java:138)                                                                           在java.lang.Integer.parseInt(Integer.java:359)                                                                           在java.lang.Integer.parseInt(Integer.java:332)                                                                           at amir.app.pro.my_timer2.MainActivity.onClick(MainActivity.java:54)                                                                           在android.view.View.performClick(View.java:4204)                                                                           在android.view.View $ PerformClick.run(View.java:17355)                                                                           在android.os.Handler.handleCallback(Handler.java:725)                                                                           在android.os.Handler.dispatchMessage(Handler.java:92)                                                                           在android.os.Looper.loop(Looper.java:137)                                                                           在android.app.ActivityThread.main(ActivityThread.java:5041)                                                                           at java.lang.reflect.Method.invokeNative(Native Method)                                                                           在java.lang.reflect.Method.invoke(Method.java:511)                                                                           在com.android.internal.os.ZygoteInit $ MethodAndArgsCaller.run(ZygoteInit.java:793)                                                                           在com.android.internal.os.ZygoteInit.main(ZygoteInit.java:560)                                                                           在dalvik.system.NativeStart.main(本地方法)

它指的是这一行:

 int noOfMinutes = Integer.parseInt(getMinutes) * 60 * 1000;

1 个答案:

答案 0 :(得分:0)

此问题是由Integer.parseInt()的行为引起的,因为这不允许空String。在调用此方法之前,您需要使用isEmpty()检查输入是否为空:

int noOfMinutes = getMinutes.isEmpty() ? 0 : Integer.parseInt(getMinutes) * 60 * 1000;
int noOfSeconds = getSeconds.isEmpty() ? 0 : Integer.parseInt(getSeconds) * 1000;