我有以下代码:
import threading
import time
class TestWorker (threading.Thread):
def __init__(self, threadID, name):
threading.Thread.__init__(self)
self.threadID = threadID
self.name = name
def run(self):
print "Starting " + self.name
time.sleep(20)
print "Exiting " + self.name
# how do I let the calling thread know it's done?
class TestMain:
def __init__(self):
pass
def do_work(self):
thread = TestWorker(1, "Thread-1")
thread.start()
def do_something_else(self):
print "Something else"
def on_work_done(self):
print "work done"
如何让主线知道TestWorker
已完成(致电on_work_done()
),而不会阻止do_something_else()
调用thread.join()
?
答案 0 :(得分:1)
您可以为线程实例提供一个可选的回调函数,以便在完成后调用
注意我添加了Lock
以防止并发打印(确实阻止)。
import threading
import time
print_lock = threading.Lock() # prevent threads from printing at same time
class TestWorker(threading.Thread):
def __init__(self, threadID, name, callback=None):
threading.Thread.__init__(self)
self.threadID = threadID
self.name = name
self.callback = callback if callback else lambda: None
def run(self):
with print_lock:
print("Starting " + self.name)
time.sleep(3)
with print_lock:
print("Exiting " + self.name)
self.callback()
class TestMain:
def __init__(self):
self.work_done = False
def do_work(self):
thread = TestWorker(1, "Thread-1", self.on_work_done)
thread.start()
def do_something_else(self):
with print_lock:
print("Something else")
def on_work_done(self):
with print_lock:
print("work done")
self.work_done = True
main = TestMain()
main.do_work()
while not main.work_done:
main.do_something_else()
time.sleep(.5) # do other stuff...
print('Done')
输出:
Starting Thread-1
Something else
Something else
Something else
Something else
Something else
Something else
Exiting Thread-1
Something else
work done
Done
答案 1 :(得分:1)
executions = data['executions']
order_id = executions[0]['orderId']
OUT:
id
答案 2 :(得分:0)
import threading
dt = {}
threading.Thread(target=dt.update, kwargs=dict(out=123)).start()
while 'out' not in dt:
print('out' in dt)
print(dt)