Question

所以我有这条路线

Route::get('/locations/{lat}/{lng}', ['as'=>'locations.find', 'uses'=> 'LocationsController@find']);

这将我带到控制器

public function Find($lat,$lng)
{


    $URLToCall = "https://maps.googleapis.com/maps/api/place/nearbysearch/json?location=".$lat.",".$lng."&key=".self::$apiKey;
    // $URLToCall = "https://maps.googleapis.com/maps/api/geocode/json?address=".urlencode($placeName)."&key=".self::$apiKey;
    $result = json_decode(file_get_contents($URLToCall),true);
    if($result['status'] == "OK") {
        $URLToCall = "https://maps.googleapis.com/maps/api/place/details/json?placeid=".$result['results'][0]['place_id']."&key=".self::$apiKey;
        $result = json_decode(file_get_contents($URLToCall),true);
        // echo $URLToCall;
        // print_r($result);
        $googlePlaceData =  $result['result'];
        $place_id = $googlePlaceData['place_id'];
        $address = $googlePlaceData['name'];

        $name = $googlePlaceData['name'];
        $lat = $googlePlaceData['geometry']['location']['lat'];
        $lng = $googlePlaceData['geometry']['location']['lng'];
        $formatted_address = $googlePlaceData['formatted_address'];
        // echo $formatted_address;
        // dd($result['result']);
        $location = LocationRepository::get($place_id, $address);

        echo $location;
        // return response()->json(json_decode($location));
    } else {
        echo "Could not Find Data";
    }
}
}

现在，当我添加新位置时，我得到了请求方法：GET 状态代码：500内部服务器错误

但是当我刷新相同的Url时，我会按照我想要的方式获取数据。问题应该是我返回数据的方式。但是我无法弄清楚我该怎么做才能搞定它。我添加一个新的lat，lng，我没有保存在我的位置数据库中。我收到这个错误。任何帮助将不胜感激。感谢

laravel中的基本重新布线

0 个答案: