Question

我仍然能够快速掌握我的Ruby技能。

我一直试图弄清楚我是否可以为rspec测试干掉这段代码：

require 'rails_helper'

RSpec.describe Role, type: :model do

    describe "has several roles types " do

        before :each do 
            @roles = Role.all
        end

        context "The role types that are valid" do
            it "includes 'proofreader', 'admin', 'super_admin' " do
                expect(@roles.any?{|r| r.name == 'proofreader'}).to be_truthy
                expect(@roles.any?{|r| r.name == 'admin'}).to be_truthy
                expect(@roles.any?{|r| r.name == 'super_admin'}).to be_truthy
            end
        end

        context "The role types that are not valid " do
            it "includes 'developer' " do
                expect(@roles.any?{|r| r.name == 'developer'}).to be_falsy
            end
        end

    end

end

具体来说，我想将这三行代码减少到一行，但是我不知道如何在一行中检查三个字符串值的ActiveRecord关系。有什么想法吗？

Answer 1

您似乎需要使用include匹配器：

it "includes 'proofreader', 'admin', 'super_admin' " do
  expect(@roles.map(&:name)).to include('proofreader', 'admin', 'super_admin')
end

此外，您可以删除before阻止，只需使用Role.pluck(:name)：

let(:roles_names) { Role.pluck(:name) }
it '...' do
  expect(roles_names).to include('proofreader', 'admin', 'super_admin')
end

如何使用更好的Ruby语法清理此测试

1 个答案: