我有一个4D numpy数组，但每个元素都是一个可变大小的3D卷。基本上它是一个numpy的3D卷列表。所以numpy数组的形状......
(Pdb) batch_x.shape
(3,)
并在该列表中使用元素i，它看起来像这样......
(Pdb) batch_x[i].shape
(7, 70, 66)
我尝试用零填充每个3D卷，使用以下代码...
for i in range(batch_size):
pdb.set_trace()
batch_x[i] = np.lib.pad(batch_x[i], (n_input_z - int(batch_x[i][:,0,0].shape[0]),
n_input_x - int(batch_x[i][0,:,0].shape[0]),
n_input_y - int(batch_x[i][0,0,:].shape[0])),
'constant', constant_values=(0,0,0))
batch_y[i] = np.lib.pad(batch_y[i], (n_input_z - int(batch_y[i][:,0,0].shape[0]),
n_input_x - int(batch_y[i][0,:,0].shape[0]),
n_input_y - int(batch_y[i][0,0,:].shape[0])),
'constant', constant_values=(0,0,0))
错误如下......
*** ValueError: Unable to create correctly shaped tuple from (3, 5, 9)
我试图填充每个3D体积，使它们具有相同的形状 - [10,75,75]。请注意，就像我上面所示，batch_x[i].shape = (7,70,66)所以错误信息至少告诉我我的尺寸应该是正确的。
有证据，调试......
(Pdb) int(batch_x[i][:,0,0].shape[0])
7
(Pdb) n_input_z
10
(Pdb) (n_input_z - int(batch_x[i][:,0,0].shape[0]))
3