Question

我使用改造来连接数据库，但GSON似乎没有解析数据。正在返回JSON，但未创建响应正文，因此我无法与数据交互。有什么想法吗？

我的网址添加

public interface APIPlug {
@FormUrlEncoded
@POST("repair_manager/v1/login")
Call<UserResults>Login(
        @Field("email") String email,
        @Field("password") String password
        );


}

我的改造构建器

public class ApiClient {

private static APIPlug REST_CLIENT;
private static final String API_URL = "http://192.168.1.85/";

static {
    setupRestClient();
}

private ApiClient() {}

public static APIPlug get() {
    return REST_CLIENT;
}

private static void setupRestClient() {

    OkHttpClient.Builder httpClient = new OkHttpClient.Builder();

    //Uncomment these lines below to start logging each request.


    HttpLoggingInterceptor logging = new HttpLoggingInterceptor();
    logging.setLevel(HttpLoggingInterceptor.Level.BODY);
    httpClient.addInterceptor(logging);


    Retrofit retrofit = new Retrofit.Builder()
            .baseUrl(API_URL)
            .addConverterFactory(GsonConverterFactory.create())
            .client(httpClient.build())
            .build();


    REST_CLIENT = retrofit.create(APIPlug.class);
}}

User.java

public class User {

    private Boolean error;

    private String name;

    private String email;

    private String apiKey;

    private String createdAt;



    public Boolean getError() {
        return error;
    }

    public void setError(Boolean error) {
        this.error = error;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public String getApiKey() {
        return apiKey;
    }

    public void setApiKey(String apiKey) {
        this.apiKey = apiKey;
    }

    public String getCreatedAt() {
        return createdAt;
    }

    public void setCreatedAt(String createdAt) {
        this.createdAt = createdAt;
    }

}

要使用的活动使用GSON

 private void getUser() {

    final String email = inputEmail.getText().toString().trim();
    final String password = inputPassword.getText().toString().trim();
Call<UserResults> call = ApiClient.get().Login(email,password);

call.enqueue(new Callback<UserResults>() {

    public void onFailure(Call<UserResults> call, Throwable t) {
        Log.d("APIPlug", "Error Occured: " + t.getMessage());

        pDialog.dismiss();
    }

public void onResponse(Call<UserResults> call, Response<UserResults> response) {
    Log.d("APIPlug", "Successfully response fetched" );

    pDialog.dismiss();

    user = response.body().results;


    Log.d("APIPlug", String.valueOf(response.body().results));

    session.setLogin(true);}});

用户结果

public class UserResults {
public List<User> results;}

okhttp log

08-15 21:18:32.753 13629-14006/com.example.maxwell.nfc_app D/OkHttp: Date: Mon, 15 Aug 2016 20:18:26 GMT
08-15 21:18:32.753 13629-14006/com.example.maxwell.nfc_app D/OkHttp: Server: Apache/2.4.18 (Win64) PHP/5.6.19
08-15 21:18:32.753 13629-14006/com.example.maxwell.nfc_app D/OkHttp: X-Powered-By: PHP/5.6.19
08-15 21:18:32.753 13629-14006/com.example.maxwell.nfc_app D/OkHttp: Content-Length: 148
08-15 21:18:32.753 13629-14006/com.example.maxwell.nfc_app D/OkHttp: Keep-Alive: timeout=5, max=100
08-15 21:18:32.753 13629-14006/com.example.maxwell.nfc_app D/OkHttp: Connection: Keep-Alive
08-15 21:18:32.753 13629-14006/com.example.maxwell.nfc_app D/OkHttp: Content-Type: application/json
08-15 21:18:32.753 13629-14006/com.example.maxwell.nfc_app D/OkHttp: {"error":false,"name":"Rachel Simon","email":"RachelSimon2@gmail.com","apiKey":"c5996a2076d7338987d8743effc56d58","createdAt":"2016-08-13 12:41:51"}
08-15 21:18:32.753 13629-14006/com.example.maxwell.nfc_app D/OkHttp: <-- END HTTP (148-byte body)

Answer 1

正如JaythaKing指出的那样，您接收的是JSONObject而不是JSONArray作为响应。所以使用Call而不是Call。

从Retrofit开始，我建议你仔细阅读：

Consuming APIs with Retrofit

学习JSON基础知识和解析：

Android JSON Parsing Tutorial

Answer 2

作为选项，您可以收到Jason的回复，然后通过any方法将其解析或反序列化到您的班级。

public interface APIPlug {
@FormUrlEncoded
@POST("repair_manager/v1/login")
Call<JsonElement>Login(
        @Field("email") String email,
        @Field("password") String password
        );

请求：

call.enqueue(new Callback<JsonElement>() {
    @Override
    public void onResponse(Call<JsonElement> call, Response<JsonElement> response) {
        if(response.isSuccessful()){
            JsonElement jsonElement = response.body();
            JsonObject objectWhichYouNeed = jsonElement.getAsJsonObject();

            //use any json deserializer to convert to your class.
        }
        else{
            System.out.println(response.message());
        }
    }
    @Override
    public void onFailure(Call<JsonElement> call, Throwable t) {
        System.out.println("Failed");
    }
});

Retrofit Body返回null

2 个答案: