Question

正如标题所示，我正在做一个教程。但是我遇到了这个错误：

>>> from words import (fetch_words, print_words)
>>> print_words(fetch_words())
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "C:\Users\jjosey\Documents\pyfund\words.py", line 12, in print_words
    for word in story_words:
TypeError: 'NoneType' object is not iterable

调用此文件时（words.py）：

from urllib.request import urlopen

def fetch_words():
    with urlopen('http://sixty-north.com/c/t.txt') as story:
        story_words = []
        for line in story:
            line_words = line.decode('utf-8').split()
            for word in line_words:
                story_words.append(word)

def print_words(story_words):               
    for word in story_words:
        print(word)

def main():
    words = fetch_words()
    print_words(words)          

if __name__ == '__main__':
    main()

我理解错误表明我正在调用空数组。但这正是导师在视频中的作用，所以我假设我在某个地方犯了一个错误，导致错误袭击了我。这是我学习Python的第一天，所以我没有发现它。

任何帮助表示赞赏。感谢

Answer 1

尝试在fetch_words末尾添加words = fetch_words()语句。如果没有它，words将导致None成为def fetch_words(): with urlopen('http://sixty-north.com/c/t.txt') as story: story_words = [] for line in story: line_words = line.decode('utf-8').split() for word in line_words: story_words.append(word) return story_words。

<module>

Answer 2

def fetch_words():
    with urlopen('http://sixty-north.com/c/t.txt') as story:
        story_words = []
        for line in story:
            line_words = line.decode('utf-8').split()
            for word in line_words:
                story_words.append(word)

此函数有一个错误...虽然您稍后尝试使用返回的值，但它不会return一个值。试试这个......

def fetch_words():
    story_words = []
    with urlopen('http://sixty-north.com/c/t.txt') as story:
        for line in story:
            line_words = line.decode('utf-8').split()
            for word in line_words:
                story_words.append(word)
    return story_words

学习Python - 语法错误阻止我继续学习

2 个答案: