我正在尝试通过套接字连接从客户端向服务器发送数据。我成功发送了第一个数据,但是当我尝试发送第二个数据时它永远不会发送,当我尝试发送第三个时它会给我Sockets.SocketException
我该如何解决?
服务器
byte[] buffer = new byte[1000];
IPHostEntry iphostInfo = Dns.GetHostEntry(Dns.GetHostName());
IPAddress ipAddress = iphostInfo.AddressList[0];
IPEndPoint localEndpoint = new IPEndPoint(ipAddress, 8080);
Socket sock = new Socket(ipAddress.AddressFamily, SocketType.Stream, ProtocolType.Tcp);
sock.Bind(localEndpoint);
sock.Listen(5);
while (true) {
Socket confd = sock.Accept();
string data = null;
int b = confd.Receive(buffer);
data += Encoding.ASCII.GetString(buffer, 0, b);
Console.WriteLine("" + data);
confd.Close();
}
客户端
byte[] data = new byte[10];
IPHostEntry iphostInfo = Dns.GetHostEntry(Dns.GetHostName());
IPAddress ipAdress = iphostInfo.AddressList[0];
IPEndPoint ipEndpoint = new IPEndPoint(ipAdress, 8080);
Socket client = new Socket(ipAdress.AddressFamily, SocketType.Stream, ProtocolType.Tcp);
try {
client.Connect(ipEndpoint);
Console.WriteLine("Socket created to {0}", client.RemoteEndPoint.ToString());
while (true) {
string message = Console.ReadLine();
byte [] sendmsg = Encoding.ASCII.GetBytes(message);
int n = client.Send(sendmsg);
}
}
catch (Exception e) {
Console.WriteLine(e.ToString());
}
Console.WriteLine("Transmission end.");
Console.ReadKey();
答案 0 :(得分:2)
好的,多么愚蠢的错误。这是解决方案,我们应该接受套接字一次。
while (true) {
Socket confd = sock.Accept();
string data = null;
int b = confd.Receive(buffer);
data += Encoding.ASCII.GetString(buffer, 0, b);
Console.WriteLine("" + data);
confd.Close();
}
已更改为
Socket confd = sock.Accept();
while (true) {
//Socket confd = sock.Accept();
string data = null;
int b = confd.Receive(buffer);
data += Encoding.ASCII.GetString(buffer, 0, b);
Console.WriteLine("" + data);
//confd.Close();
}
如果有任何关于套接字的文档,请发表评论。我想读一读。