Question

我想在这个JSON上得到“字典的关键字”（这就是我所说的，不确定它是否是正确的名称）

{
  "People": {
    "People with nice hair": {
      "name": "Peter John",
      "age": 12,
      "books": [
        {
          "title": "Breaking Bad",
          "release": "2011"
        },
        {
          "title": "Twilight",
          "release": "2012"
        },
        {
          "title": "Gone Wild",
          "release": "2013"
        }
      ]
    },
    "People with jacket": {
      "name": "Jason Bourne",
      "age": 15,
      "books": [
        {
          "title": "Breaking Bad",
          "release": "2011"
        },
        {
          "title": "Twilight",
          "release": "2012"
        },
        {
          "title": "Gone Wild",
          "release": "2013"
        }
      ]
    }
  }
}

首先，我已经创建了我的People结构，用于从那些JSON映射。这是我的人员结构

struct People {
    var peopleLooks:String?
    var name:String?
    var books = [Book]()
}

这是我的Book结构

struct Book {
    var title:String?
    var release:String?
}

从那个JSON，我用Alamofire和SwiftyJSON创建了引擎，它将通过完成处理程序在我的控制器中调用

Alamofire.request(request).responseJSON { response in
   if response.result.error == nil {
      let json = JSON(response.result.value!)
      success(json)
   }
}

这就是我在控制器中所做的事情

Engine.instance.getPeople(request, success:(JSON?)->void),
   success:{ (json) in

   // getting all the json object
   let jsonRecieve = JSON((json?.dictionaryObject)!)

   // get list of people
   let peoples = jsonRecieve["People"]

   // from here, we try to map people into our struct that I don't know how.
}

我的问题是，如何将peoples从jsonRecieve["People"]映射到我的结构中？我希望在"People with nice hair"结构中将peopleLooks作为People的值。我认为"People with nice hair"是词典或其他东西的关键，但我不知道如何得到它。

任何帮助将不胜感激。谢谢！

Answer 1

在迭代字典时，例如

for peeps in peoples

您可以使用

访问密钥

peeps.0

和

的值

peeps.1

Answer 2

您可以使用键值循环。

for (key,subJson):(String, JSON) in json["People"] {
   // you can use key and subJson here.
}

使用SwiftyJSON获取JSON解析中的字典密钥

2 个答案: