Question

我有这个查询

fa-5x

从查询中我得到了这个结果

SELECT 
    d.Nip,d.FullName,b.*,c.InTime,c.OutTime, 
    (SELECT DATEPART(HOUR, OutTime)) - (SELECT DATEPART(HOUR, InTime)) as lebih 
FROM 
    DinasAuditHeader a 
INNER JOIN
    DinasAuditDetail b on a.KodeAuditHeader = b.KodeAuditHeader 
INNER JOIN
    Attendance c on b.Nip = c.Nip and b.attendancedate = c.AttendanceDate 
INNER JOIN
    employee d on c.Nip = d.Nip 
WHERE
    b.Nip = '1502427' 
    AND c.AttendanceCode = 'P3' 
    AND a.KodeAuditHeader = 'AD0000001'

从我的查询和结果中可以看出。我有一个名为Nip FullName KodeDetailDinas KodeAuditHeader nip AttendanceDate claim_status InTime OutTime lebih 1502427 FERNANDO ALIM 1 AD0000001 1502427 2016-08-28 0 2016-08-28 08:55:00.000 2016-08-28 21:03:00.000 13 1502427 FERNANDO ALIM 3 AD0000001 1502427 2016-08-30 0 2016-08-30 08:55:00.000 2016-08-30 18:03:00.000 10 1502427 FERNANDO ALIM 2 AD0000001 1502427 2016-08-29 0 2016-08-29 08:55:00.000 2016-08-29 19:03:00.000 11 1502427 FERNANDO ALIM 4 AD0000001 1502427 2016-08-31 0 2016-08-31 08:50:00.000 2016-08-31 20:03:00.000 12的列。 lebih是lebih和InTime之间的结果范围。

我有两个问题。

从我上面的查询中我只能获得OutTime。那么如何使用这种格式hour
如何查看它们之间的范围（hh:mm - OutTime），然后用InTime减去？

Answer 1

您可以尝试SELECT CONVERT(VARCHAR(5),(OutTime - InTime),108) AS lebih

下面的Sql查询应该适用于您的情况：

SELECT 
    d.Nip,d.FullName,b.*,c.InTime,c.OutTime, 
    CONVERT(VARCHAR(5),(OutTime - InTime),108) AS lebih
FROM 
    DinasAuditHeader a 
INNER JOIN
    DinasAuditDetail b on a.KodeAuditHeader = b.KodeAuditHeader 
INNER JOIN
    Attendance c on b.Nip = c.Nip and b.attendancedate = c.AttendanceDate 
INNER JOIN
    employee d on c.Nip = d.Nip 
WHERE
    b.Nip = '1502427' 
    AND c.AttendanceCode = 'P3' 
    AND a.KodeAuditHeader = 'AD0000001'

<强>更新

要从lebih中减去8小时，您可以使用

CONVERT(VARCHAR(5), DATEADD(HOUR, -8, OutTime - InTime), 108) AS lebih

Answer 2

问题编号1.你可以使用@Unnikrishnan R回答。然后对于第二个，请尝试下面的查询。

SELECT 
    d.Nip,d.FullName,b.*,c.InTime,c.OutTime, LEFT(CAST(DATEADD(MINUTE,DATEDIFF(MINUTE,InTime,OutTime),'2011-01-01 00:00') AS TIME),5) lebih ,
    LEFT(CAST(DATEADD(MINUTE,DATEDIFF(MINUTE,InTime,DATEADD(HOUR, -8, OutTime)),'2011-01-01 00:00') AS TIME),5) 
FROM DinasAuditHeader a 
 INNER JOIN DinasAuditDetail b on a.KodeAuditHeader = b.KodeAuditHeader 
 INNER JOIN Attendance c on b.Nip = c.Nip and b.attendancedate = c.AttendanceDate 
 INNER JOIN employee d on c.Nip = d.Nip 
WHERE b.Nip = '1502427' and c.AttendanceCode = 'P3' and a.KodeAuditHeader = 'AD0000001'
order by KodeDetailDinas asc

Answer 3

VARCHAR后附加到':00'的简单投射怎么样？

SELECT 
    d.Nip,d.FullName,b.*,c.InTime,c.OutTime, 
    cast((SELECT DATEPART(HOUR, OutTime)) - (SELECT DATEPART(HOUR, InTime)) AS VARCHAR(2)) + ':00' as lebih 
    FROM DinasAuditHeader a 
    inner join DinasAuditDetail b on a.KodeAuditHeader = b.KodeAuditHeader 
    inner join Attendance c on b.Nip = c.Nip and b.attendancedate = c.AttendanceDate 
    inner join employee d on c.Nip = d.Nip 
where b.Nip = '1502427' and c.AttendanceCode = 'P3' and a.KodeAuditHeader = 'AD0000001'

如果您想使其精确到MINUTE，请更好地使用DATEDIFF

select 
    d.Nip,d.FullName,b.*,c.InTime,c.OutTime, 
    cast(DATEDIFF(MINUTE, InTime, OutTime) / 60) as varchar(2)) + ':' 
    + cast(DATEDIFF(MINUTE, InTime, OutTime) % 60) as varchar(2))
    FROM DinasAuditHeader a 
    inner join DinasAuditDetail b on a.KodeAuditHeader = b.KodeAuditHeader 
    inner join Attendance c on b.Nip = c.Nip and b.attendancedate = c.AttendanceDate 
    inner join employee d on c.Nip = d.Nip 
where b.Nip = '1502427' and c.AttendanceCode = 'P3' and a.KodeAuditHeader = 'AD0000001'

如果您希望将时间结果进一步缩短8小时，则可以先将OutTime 8小时后退。

select 
    d.Nip,d.FullName,b.*,c.InTime,c.OutTime, 
    cast(DATEDIFF(MINUTE, InTime, DATEADD(HOUR, -8, OutTime)) / 60) as varchar(2)) + ':' 
    + cast(DATEDIFF(MINUTE, InTime, DATEADD(HOUR, -8, OutTime)) % 60) as varchar(2))
    FROM DinasAuditHeader a 
    inner join DinasAuditDetail b on a.KodeAuditHeader = b.KodeAuditHeader 
    inner join Attendance c on b.Nip = c.Nip and b.attendancedate = c.AttendanceDate 
    inner join employee d on c.Nip = d.Nip 
where b.Nip = '1502427' and c.AttendanceCode = 'P3' and a.KodeAuditHeader = 'AD0000001'

Answer 4

使用脚本获取'HH：MM'的时差。

SELECT 
    d.Nip,d.FullName,b.*,c.InTime,c.OutTime, 
    LEFT(CAST(DATEADD(MINUTE,DATEDIFF(MINUTE,InTime,OutTime),'2011-01-01 00:00') AS TIME),5) as lebih
FROM DinasAuditHeader a 
 INNER JOIN DinasAuditDetail b on a.KodeAuditHeader = b.KodeAuditHeader 
 INNER JOIN Attendance c on b.Nip = c.Nip and b.attendancedate = c.AttendanceDate 
 INNER JOIN employee d on c.Nip = d.Nip 
WHERE b.Nip = '1502427' and c.AttendanceCode = 'P3' and a.KodeAuditHeader = 'AD0000001'

查看示例查询的结果。 Time difference in HH:MM

Datepart结果格式为时间

4 个答案: