Question

我正在尝试从此链接解析json响应： https://www.move2mart.com/wp-json/wp/v2/pages?slug=watches 无论我做什么，这都是我得到的。 W / System.err：位置0处的意外字符（）。

    public class MainActivity extends AppCompatActivity {

    TextView textView;
    String url="https://www.move2mart.com/wp-json/wp/v2/pages?slug=mens-fashion";

    @Override
    protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    textView= (TextView) findViewById(R.id.text);

    final RequestQueue requestQueue = Volley.newRequestQueue(this);

    StringRequest stringRequest = new StringRequest(Request.Method.GET, url, new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {

            textView.setText(response);
            JSONParser jsonParser = new JSONParser();

                Log.d("Inside","1");
            try {
                Log.d("Inside","2");

                org.json.JSONArray jsonArray = (org.json.JSONArray) jsonParser.parse(response);



                try {
                    //org.json.JSONArray jsonObject=jsonArray.getJSONArray(0);
                    JSONObject jsonObject2 = (JSONObject) jsonParser.parse(new InputStreamReader(new FileInputStream(jsonArray.getString(0))));
                    String t1=jsonObject2.getString("id");
                    Log.d("Inside3",t1);
                } catch (JSONException e) {
                    e.printStackTrace();
                } catch (FileNotFoundException e) {
                    e.printStackTrace();
                } catch (IOException e) {
                    e.printStackTrace();
                }


            } catch (ParseException e) {
                e.printStackTrace();
            }


        }
    },
            new Response.ErrorListener() {
                @Override
                public void onErrorResponse(VolleyError error) {

                }
            });

    requestQueue.add(stringRequest);
}

}

日志响应：08-15 08：40：46.266   18845-18845 / com.example.princ.learningjsonvolly D / Inside：1

08-15 08：40：46.266 18845-18845 / com.example.princ.learningjsonvolly   D /内部：2

08-15 08：40：46.267 18845-18845 / com.example.princ.learningjsonvolly   W / System.err：位置0处的意外字符（）。

08-15 08：40：46.268 18845-18845 / com.example.princ.learningjsonvolly   W / System.err：at   org.json.simple.parser.Yylex.yylex（Yylex.java:610）

08-15 08：40：46.268 18845-18845 / com.example.princ.learningjsonvolly   W / System.err：at   org.json.simple.parser.JSONParser.nextToken（JSONParser.java:269）

Answer 1

看起来像你在gzip编码中的响应，所以让make GzipRequest：

public class GZipRequest extends StringRequest {

    public GZipRequest(int method, String url, Response.Listener<String> listener, Response.ErrorListener errorListener) {
        super(method, url, listener, errorListener);
    }

    public GZipRequest(String url, Response.Listener<String> listener, Response.ErrorListener errorListener) {
        super(url, listener, errorListener);
    }

    // parse the gzip response using a GZIPInputStream
    @Override
    protected Response<String> parseNetworkResponse(NetworkResponse response) {
        String output = ""; // note: better to use StringBuilder

        try {
            final GZIPInputStream gStream = new GZIPInputStream(new ByteArrayInputStream(response.data));
            final InputStreamReader reader = new InputStreamReader(gStream);
            final BufferedReader in = new BufferedReader(reader);
            String read;
            while ((read = in.readLine()) != null) {
                output += read;
            }
            reader.close();
            in.close();
            gStream.close();
        } catch (IOException e) {
            return Response.error(new ParseError());
        }
        return Response.success(output, HttpHeaderParser.parseCacheHeaders(response));
    }
}

在代码中修改一下：

GZipRequest stringRequest = new GZipRequest(Request.Method.GET, url, new Response.Listener<String>() {
    @Override
    public void onResponse(String response) {

        textView.setText(response);

        try {
            org.json.JSONObject jsonObject = new org.json.JSONObject(response);

            String t1 = jsonObject.getString("id");

        } catch (ParseException e) {
            e.printStackTrace();
        }


    }
}, new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError error) {

            }
        });

W / System.err：位置0处的意外字符（）

1 个答案: