Question

我对SQL查询有疑问，我无法挺身而出。我想将表格的前10个值中的SUM作为一列，将其余SUM作为另一列，以制作一个PIE图表，显示top10占整体的百分比：

我现在可以拿到剩下的或者排名前10但不是一排的摊位：

SELECT 
    SUM(counted) as Rest
FROM 
    Northeast 
WHERE 
    counted < (SELECT counted 
               FROM Northeast 
               ORDER BY counted DESC
               LIMIT 10)

任何解决方案？

Answer 1

大多数数据库都支持row_number()，因此您可以执行以下操作：

select sum(case when seqnum <= 10 then counted end) as top10_counted,
       sum(case when seqnum > 10 then counted else 0 end) as rest
from (select ne.*,
             row_number() over (order by counted) as seqnum
      from northeast ne
     ) ne;

编辑：

在SQLite中，你可以这样做：

select (select sum(counted) 
        from (select ne.* from northeast ne order by counted desc limit 10)
       ) as top10,
       (select sum(counted)
        from northeast
        where counted not in (select counted from northeast order by counted desc limit 10)
       ) as rest;

这是有效的，假设您与数据没有联系。

一个）我想不知道，上面的代码完成了工作：）

SQL获得前10名，其余分为两列

1 个答案: