内容位于文本文件的list[info]
中:
1,1,1703,385,157,339,1,-1,-1,-1
1,3,1293,455,83,213,1,-1,-1,-1
1,4,259,449,101,261,1,-1,-1,-1
1,5,1253,529,55,127,1,-1,-1,-1
2,1,1699,383,159,341,1,-1,-1,-1
2,3,1293,455,83,213,1,-1,-1,-1
2,4,261,447,101,263,1,-1,-1,-1
2,5,1253,529,55,127,1,-1,-1,-1
3,1,1697,383,159,343,1,-1,-1,-1
3,3,1293,455,83,213,1,-1,-1,-1
3,4,263,447,101,263,1,-1,-1,-1
3,5,1255,529,55,127,1,-1,-1,-1
4,1,1695,383,159,343,1,-1,-1,-1
4,3,1293,455,83,213,1,-1,-1,-1
4,4,265,447,101,263,1,-1,-1,-1
4,5,1257,529,55,127,1,-1,-1,-1
.
.
.
它们就像这些
我要展示一些照片。所以我认为你不必关心image_list和文件。无论如何,我想读这些:
结论=如果info [0]为1,我想读取info [2],info [3],info [4] info [5],它们以info [0]为1开始的行开始。
换句话说,
如果info [0]为1,我想打印如下
1703,385,157,339
1293,455,83,213
259,449,101,261
1253,529,55,127
同时
我的代码如下:
**marks = [int(info[0])]
for i, images_files in zip(marks, image_list):
for s in range(i, i):
print int(info[2]), int(info[3]), int(info[4]), int(info[5])**
请帮帮我:)。
答案 0 :(得分:2)
您可以创建一个整数值字典,列出您要打印的四个值:
from collections import defaultdict
lines = [
'1,1,1703,385,157,339,1,-1,-1,-1',
'1,3,1293,455,83,213,1,-1,-1,-1',
'1,4,259,449,101,261,1,-1,-1,-1',
'1,5,1253,529,55,127,1,-1,-1,-1',
'2,1,1699,383,159,341,1,-1,-1,-1',
'2,3,1293,455,83,213,1,-1,-1,-1',
'2,4,261,447,101,263,1,-1,-1,-1',
'2,5,1253,529,55,127,1,-1,-1,-1',
'3,1,1697,383,159,343,1,-1,-1,-1',
'3,3,1293,455,83,213,1,-1,-1,-1',
'3,4,263,447,101,263,1,-1,-1,-1',
'3,5,1255,529,55,127,1,-1,-1,-1',
'4,1,1695,383,159,343,1,-1,-1,-1',
'4,3,1293,455,83,213,1,-1,-1,-1',
'4,4,265,447,101,263,1,-1,-1,-1',
'4,5,1257,529,55,127,1,-1,-1,-1',
]
line_map = defaultdict(list)
for line in lines:
values = line.split(',')
line_map[int(values[0])].append(','.join(values[2:6]))
print line_map[1] # ['1703,385,157,339', '1293,455,83,213', '259,449,101,261', '