在Laravel View中使用2个不同的SQL查询

时间:2016-08-14 16:50:49

标签: php laravel laravel-4 laravel-5

我正在尝试在我的主页上显示2列不同的

我有BrowseController.php个文件:

 /**
 * @return mixed
 */
public function getTrending()
{
    $posts = $this->posts->getTrending(null, ['category' => Input::get('category'), 'timeframe' => Input::get('timeframe')]);

    return View::make('post.list')->with('title', t('Trending'))->with('posts', $posts);
}

/**
 * @return mixed
 */
public function getLatest()
{
    $posts = $this->posts->getLatest(null, ['category' => Input::get('category'), 'timeframe' => Input::get('timeframe')]);
    $title = t('Latest');

    return View::make('post.list', compact('title', 'posts'));
}

PostsRepository.php文件:

public function getTrending($type = null, $param = [])
{
    isset($param['timeframe']) ? $param['timeframe'] = $param['timeframe'] : $param['timeframe'] = 'month';

    $posts = $this->posts($type, $param)->with('comments', 'votes', 'category', 'user', 'votes.user')
        ->leftJoin('votes', 'posts.id', '=', 'votes.post_id')
        ->leftJoin('comments', 'posts.id', '=', 'comments.post_id')
        ->select('posts.*', DB::raw('count(votes.post_id)*5 as popular'))
        ->groupBy('posts.id')->with('user')->orderBy('popular', 'desc');

    $posts = $posts->paginate(perPage());

    return $posts;
}

public function getLatest($type = null, $param = [])
{
    $posts = $this->posts($type, $param)->with('comments', 'votes', 'category', 'user', 'votes.user')->orderBy('approved_at', 'desc')->paginate(perPage());

    return $posts;
}

在我的刀片php文件中,我试图使用这2个函数但只有一个正在工作,因为在我的routes.php文件中我有这个:

Route::get('/', ['as' => 'home', 'uses' => 'BrowseController@getLatest']);

所以@foreach($posts as $post) @endif仅加载getLatest而不加载getTrending

任何人都可以帮助我吗?

1 个答案:

答案 0 :(得分:0)

您已告知您的路由使用getTrending()控制器方法,但getLatest()调用完全存在于另一种方法中。如果要在同一页面中显示最新和趋势帖子,请将两个方法调用合并为一个控制器方法:

// BrowseController.php

public function getLatestAndTrending()
{
    $trendingPosts = $this->posts->getTrending(null, ['category' => Input::get('category'), 'timeframe' => Input::get('timeframe')]);

    $latestPosts = $this->posts->getLatest(null, ['category' => Input::get('category'), 'timeframe' => Input::get('timeframe')]);

    return View::make('post.list')
        ->with('title', t('New and trending'))
        ->with('trendingPosts', $trendingPosts)
        ->with('latestPosts', $latestPosts);
}

将路线更改为指向getLatestAndTrending控制器方法:

Route::get('/', ['as' => 'home', 'uses' => 'BrowseController@getLatestAndTrending']);

然后在您看来,可以分别迭代趋势和最新帖子:

@foreach($trendingPosts as $post)
    // ...
@endforeach

@foreach($latestPosts as $post)
    // ...
@endforeach