当我在网站上看到很多教程时,他们大多数都在java中定义String数据,如String [] data = {“value”,“value2”,“value3”};但它不是实时应用中的正确方法我想。在我的应用程序中,我也将使用其他语言,所以我需要在xml中定义。无论我使用下面的代码调用它们:
onCreateView
String[] eArray=getActivity().getResources().getStringArray(R.array.english_names);
并将其称为
names.add(new Name(eArray));
但当我将鼠标悬停在eArray上时,它显示的错误如Name中的Name(java.lang.String)无法应用于(java.lang.String [])
我知道我必须将其他值传递给数组但是如何?我改变了错误行,它不断显示其他和其他。我谷歌很多tuts网站,但所有这些都是务实地定义字符串。
我制作了一个自定义的recyclerview,下面是它的代码
cardview.xml
<?xml version="1.0" encoding="utf-8"?>
<android.support.v7.widget.CardView xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
android:id="@+id/cardview"
android:layout_width="match_parent"
android:layout_height="wrap_content"
app:cardCornerRadius="8dp"
app:cardUseCompatPadding="true"
app:cardBackgroundColor="@android:color/transparent"
android:elevation="0dp">
<TextView
android:id="@+id/textView"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:textSize="25sp"
android:paddingLeft="10dp"
android:textColor="#4928ef"
android:textStyle="italic"/>
</android.support.v7.widget.CardView>
recyclerview.xml
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical" android:layout_width="match_parent"
android:layout_height="match_parent"
android:id="@+id/linearlayout"
android:background="@drawable/big_img_boy_wp">
<android.support.v7.widget.RecyclerView
android:layout_width="match_parent"
android:layout_height="match_parent"
android:id="@+id/rv">
</android.support.v7.widget.RecyclerView>
</LinearLayout>
cardview.java
public class cardView extends Fragment {
TextView textView;
@Nullable
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View view=inflater.inflate(R.layout.card_view,container,false);
textView= (TextView) view.findViewById(R.id.textView);
// Typeface typeface=Typeface.createFromAsset(getActivity().getAssets(),"fonts/Cavorting.otf");
// textView.setTypeface(typeface);
return view;
}
}
Name.java
public class Name {
String textView;
Name(String textView){
this.textView=textView;
}
}
recycler.java
public class Recycler extends Fragment {
private List<Name> names;
RecyclerView rv;
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View view=inflater.inflate(R.layout.recyclerview,container,false);
rv= (RecyclerView) view.findViewById(R.id.rv);
String[] eArray=getActivity().getResources().getStringArray(R.array.english_names);
LinearLayoutManager llm=new LinearLayoutManager(getActivity());
rv.setLayoutManager(llm);
rv.setHasFixedSize(true);
initializeData();
initializeAdapter();
return view;
}
private void initializeAdapter() {
rvadapter adapter=new rvadapter(names);
rv.setAdapter(adapter);
}
public void initializeData() {
names=new ArrayList<>();
names.add(new Name("Anish"));
names.add(new Name(eArray));
}
}
rvadapter.java
public class rvadapter extends RecyclerView.Adapter<rvadapter.NameViewHolder> {
public static class NameViewHolder extends RecyclerView.ViewHolder{
CardView cv;
TextView textView;
public NameViewHolder(View itemView) {
super(itemView);
cv= (CardView) itemView.findViewById(R.id.cardview);
textView= (TextView) itemView.findViewById(R.id.textView);
}
}
List<Name> names;
public rvadapter(List<Name> names) {
this.names=names;
}
@Override
public void onAttachedToRecyclerView(RecyclerView recyclerView) {
super.onAttachedToRecyclerView(recyclerView);
}
@Override
public NameViewHolder onCreateViewHolder(ViewGroup parent, int viewType) {
View v= LayoutInflater.from(parent.getContext()).inflate(R.layout.card_view,parent,false);
NameViewHolder nvh=new NameViewHolder(v);
return nvh;
}
@Override
public void onBindViewHolder(NameViewHolder holder, int position) {
holder.textView.setText(names.get(position).textView);
}
@Override
public int getItemCount() {
return names.size();
}
}
还请看看我的cardview.java,我把评论,这个字体也没有改变。我把字体放在资产然后字体文件夹。这是我在stackoverflow中的第二个问题,但我的第一个问题是没有正确回答,如果你可以请看看Click here to to look by another problem too.提前致谢!!
答案 0 :(得分:0)
for (int i = 0; i < eArray.length; i++) {
names.add(new Name(eArray[i]));
}