Question

我是python的新手，我正在开发一个需要将字典写入文本文件的项目。格式如下：

{'17': [('25', 5), ('23', 3)], '12': [('28', 3), ('22', 3)], '13': [('28', 3), ('23', 3)], '16': [('22', 3), ('21', 3)], '11': [('28', 3), ('29', 1)], '14': [('22', 3), ('23', 3)], '15': [('26', 2), ('24', 2)]}.

如您所见，字典中的值始终是列表。我想在下面写入文本文件： 17,25,5 \ n 17,23,3 \ n 12,28,3 \ n 12,22,3 \ n 13,28,3 \ n 13,23,3 \ n ... \ n代表新行

这意味着，要为列表中的每个值重复的键都属于＆＃39;那些钥匙。原因是因为我需要再次将文本文件读入数据库以进行进一步分析。尝试搜索过去几天的答案并尝试了很多方法，只是无法使其成为这种格式。感谢您是否有任何解决方案。非常感谢！

Answer 1

>>> for k, v in data.items():
...     for t in v:
...        print "%s, %s, %s" % ((k,) +t)
... 
11, 28, 3
11, 29, 1
13, 28, 3
13, 23, 3
12, 28, 3
12, 22, 3
15, 26, 2
15, 24, 2
14, 22, 3
14, 23, 3
17, 25, 5
17, 23, 3
16, 22, 3
16, 21, 3
>>>

首先获取每个键和值（它们是元组）。然后循环遍历元组并使用键打印每个元组值。请注意，字典不是有序的，因此结果可能不会按字典顺序排列

Answer 2

这是一个工作示例，向您展示如何将字典转储到字符串，首先没有任何特定顺序，然后按键排序，选择您想要的：

data = {
    '17': [('25', 5), ('23', 3)],
    '12': [('28', 3), ('22', 3)],
    '13': [('28', 3), ('23', 3)],
    '16': [('22', 3), ('21', 3)],
    '11': [('28', 3), ('29', 1)],
    '14': [('22', 3), ('23', 3)],
    '15': [('26', 2), ('24', 2)]
}

lines = []
for k, v in data.iteritems():
    for tupl in v:
        row = [k] + map(lambda x: str(x), list(tupl))
        lines.append(', '.join(row))

output = '\n'.join(lines)
print output
print '-' * 80

lines = []
for k, v in sorted(data.iteritems()):
    for tupl in v:
        row = [k] + map(lambda x: str(x), list(tupl))
        lines.append(', '.join(row))

sorted_output = '\n'.join(lines)
print sorted_output

修改

上面的代码是为了与python 2.x一起编写的，这里是3.x版本：

data = { '17': [('25', 5), ('23', 3)], '12': [('28', 3), ('22', 3)], '13': [('28', 3), ('23', 3)], '16': [('22', 3), ('21', 3)], '11': [('28', 3), ('29', 1)], '14': [('22', 3), ('23', 3)], '15': [('26', 2), ('24', 2)] } lines = [] for k, v in data.items(): for tupl in v: row = [k] + list(map(lambda x: str(x), list(tupl))) lines.append(', '.join(row)) output = '\n'.join(lines) print(output) print('-' * 80) lines = [] for k, v in sorted(data.items()): for tupl in v: row = [k] + list(map(lambda x: str(x), list(tupl))) lines.append(', '.join(row)) sorted_output = '\n'.join(lines) print(sorted_output)

Answer 3

假设散列值由包含大小为2的元组的列表组成。

>>> f = open('test.txt', 'w')
>>> for key,value in d.iteritems():
...  for v in value:
...     f.write(key + ' ' + v[0] + ' ' + str(v[1]) + '\n')
... 
>>> f.close()

test.txt中的值将为

11, 28, 3
11, 29, 1
13, 28, 3
13, 23, 3
12, 28, 3
12, 22, 3
15, 26, 2
15, 24, 2
14, 22, 3
14, 23, 3
17, 25, 5
17, 23, 3
16, 22, 3
16, 21, 3

将包含值列表的字典写入文本文件，并为列表中的每个元素重复键

3 个答案: