Question

function player(name, goals, games) {
    this.name = name;
    this.goals = goals;
    this.games = games;
}

var ricky = new player('Ricky', 7, 15);
var tom = new player('Tom', 15, 17);
var phil = new player('Phillip', 9, 14);
var jerry = new player('Jerry', 11, 15);
var randy = new player('Randy', 4, 16);
var sam = new player('Sam', 5, 11);


function locTeams(name, town, wins, playerOne, playerTwo, playerThree) {
    this.name = name;
    this.town = town;
    this.wins = wins;
    this.playerOne = playerOne;
    this.playerTwo = playerTwo;
    this.playerThree = playerThree;
}

var tigers = new locTeams('Great Tigers', 'Clayton', 9, ricky, tom);
var pantheon = new locTeams('The Pantheons', 'Brookedale', 8, jerry, randy);

teams = [tigers, pantheon];

var totalGoalsState =

我需要一种简单的方法让totalGoalsState等于teams数组中玩家的累积玩家目标。另外，如何将playerThree与其他新玩家（例如phil或sam）填充到其中一个像老虎或万神队这样的团队中。

Answer 1

这是为阵容中的所有球队添加目标的一种方法，迭代并减少每个球员，每个球队等的值。

function player(name, goals, games) {
    this.name = name;
    this.goals = goals;
    this.games = games;
}
function player(name, goals, games) {
    this.name = name;
    this.goals = goals;
    this.games = games;
}

var ricky = new player('Ricky', 7, 15);
var tom = new player('Tom', 15, 17);
var phil = new player('Phillip', 9, 14);
var jerry = new player('Jerry', 11, 15);
var randy = new player('Randy', 4, 16);
var sam = new player('Sam', 5, 11);


function locTeams(name, town, wins, playerOne, playerTwo, playerThree) {
    this.name = name;
    this.town = town;
    this.wins = wins;
    this.playerOne = playerOne;
    this.playerTwo = playerTwo;
    this.playerThree = playerThree;
}

var tigers = new locTeams('Great Tigers', 'Clayton', 9, ricky, tom);
var pantheon = new locTeams('The Pantheons', 'Brookedale', 8, jerry, randy);

var teams = [tigers, pantheon];

function getGoals(team) {
		return Object.keys(team).map(function(k) {
    	return k.indexOf('player') === 0 ? 
          team[k] && "goals" in team[k] ? team[k].goals : 0 : 0;
    }).reduce(function(a,b) { return a+b });
}

var totalGoalsState = teams.reduce(function(a,b) {return getGoals(a) + getGoals(b)});

console.log(totalGoalsState)

Answer 2

如果您需要第三个玩家，只需将其添加到其他两个玩家的位置即可。请注意，我正在消除重复，因为每个玩家只能计入一次总目标。

function player(name, goals, games) {
    this.name = name;
    this.goals = goals;
    this.games = games;
}

var ricky = new player('Ricky', 7, 15);
var tom = new player('Tom', 15, 17);
var phil = new player('Phillip', 9, 14);
var jerry = new player('Jerry', 11, 15);
var randy = new player('Randy', 4, 16);
var sam = new player('Sam', 5, 11);


function locTeams(name, town, wins, playerOne, playerTwo, playerThree) {
    this.name = name;
    this.town = town;
    this.wins = wins;
    this.playerOne = playerOne;
    this.playerTwo = playerTwo;
}

var tigers = new locTeams('Great Tigers', 'Clayton', 9, ricky, tom);
var pantheon = new locTeams('The Pantheons', 'Clayton', 9, jerry, randy);

teams = [tigers, pantheon];

var totalGoalsState = teams.reduce((p, c) => p.concat([c.playerOne, c.playerTwo]), [])
                           .reduce((p, c) => p.includes(c) ? p : p.concat(c), [])
                           .reduce((p, c) => p + c.goals, 0);

console.log(totalGoalsState);

对象中

2 个答案: