Question

尝试将2个模型纳入我的＆＃34;赛季＆＃34;我的django网站上的视图/模板。目前，我得到以下作为ValueError＆＃34;视图webapp.views.season没有返回HttpResponse对象。它返回了None。＆＃34;不确定我做错了什么，但希望有人可以看看。

views.py

from django.shortcuts import render, get_object_or_404, redirect
from django.views.generic import ListView
from .models import Player, Season

def home(request):
    seasons = Season.objects.order_by('sid')
    return render(request, 'webapp/home.html', {'seasons': seasons})

def player(request, pk):
    player = get_object_or_404(Player, pk=pk)
    return render(request, 'webapp/player.html', {'player': player})

def season(ListView, pk):
    model = Season
    template_name = 'webapp/season.html'

    def get_context_data(self, **kwargs):
        context = super(season, self).get_context_data(**kwargs)
        context['players'] = Player.objects.all()
        return context

def seasons(request):
    seasons = Season.objects.order_by('sid')
    return render(request, 'webapp/seasons.html', {'seasons': seasons})

urls.py

from django.conf.urls import url
from . import views

urlpatterns = [
    url(r'^$', views.home, name='home'),
    url(r'^player/(?P<pk>\d+)/$', views.player, name='player'),
    url(r'^season/(?P<pk>\d+)/$', views.season, name='season'),
    url(r'^seasons/$', views.seasons, name='seasons'),
]

应该注意的是，我最初有一个TypeError，表示＆＃34; season（）得到了一个意想不到的关键字参数＆＃39; pk＆＃39;＆＃34;在我将pk添加到赛季论证之前。任何帮助是极大的赞赏！谢谢！

Answer 1

观看次数：home，player和seasons是Function Based Views，这是旧的Django Views风格。另一方面，ListView是Class Based View，是在Django中编写视图的新方法。你混合了两种观点，这是一个坏主意。不知道你的season视图应该做什么，但尝试类似：

def season(request, pk):
    season = get_object_or_404(Season, pk=pk) 
    return render(
        request, 
        'webapp/season.html',
        {'season': season, 'players': Player.objects.all()}
    )

Answer 2

在网址中，您需要调用基于类的视图，例如views.season.as_view（）

Django中单个视图/模板上的多个模型

2 个答案: