Question

我一直在努力学习Ruby，所以我可以建立一个网站，并被告知学习Ruby the Hard Way是一个很好的起点。我一直在做练习，但卡在ex36。我们应该写一个基于迷你文本的决策游戏（选择你的冒险风格）。我写了我的想法，并认为它是有道理的，我正在尝试一些新的功能。

我试图让一些变量随着玩家在故事中的变化而变化，结局取决于这些变量（灵魂，生命，财富，债务）。

我拿走了讲述者，但留下了双引号

soul = 1 
life = 1
riches = 0
debt = 0


def score
    if soul == 1 && life == 1
        puts ""
        gold_score
    elsif soul <= 0 && life == 1
        puts ""
        puts ""
        gold_score
    elsif soul > 1 && life == 1
        puts ""
        gold_score
    else
        puts ""
        exit(0)
    end
end

def gold_score
    if riches == 0 || debt == 0
        puts ""
        exit(0)
    elsif riches == 0 || debt == -1
        puts ""
        exit(0)

    elsif riches == 1 || debt == 0
        puts ""
        exit(0)
    else
        puts ""
        exit(0)
    end
end

def dead(why)
    puts ""
    life = 0
    score
end

def start 
    puts ""
    puts ""

    print "> "
    choice = $stdin.gets.chomp

    if choice == "left" || choice == "Left"
        pirates_room
    elsif choice == "right" || choice == "Right"
        trex_room
    else
        dead("")
    end

end

def gold_room
    puts ""
    puts ""
    puts ""
    puts "."
    puts ""
    puts ""

    print "> "
    choice = $stdin.gets.chomp

    if choice == "1" 
        puts ""
        soul = soul + 1
        score
    elsif choice == "2"
        puts ""
        riches = riches + 1
        score
    else
        puts ""
        puts ""
        score
    end
end

def pirates_room
    puts ""
    puts ""
    puts ""
    puts ""

    print "> "
    choice = $stdin.gets.chomp

    if choice.include? ""
        puts ""
        dead("")
    elsif choice.include?("beer") || choice.include?("keg") 
        puts ""
        puts ""
        puts ""
        soul = soul - 1
        gold_room
    elsif choice.include?("Cthulhu") || choice.include?("bible")
        puts ""
        puts ""
        puts ""
        puts ""
        debt = -1
        puts ""
        gold_room
    else
        pirates_room
    end
end

def trex_room
    puts ""
    puts ""
    puts ""

    print "> "
    choice = $stdin.gets.chomp

    if choice.include?("stay") || choice.include?("Stay")
        dead("")
    elsif choice.include?("pray") || choice.include?("Pray")
        puts ""
        puts ""
        puts ""
        puts ""
        puts ""
        gold_room
    else
        trex_room
    end
end

start

我跑了，问题似乎与我放在开始的变量有关。每次我尝试“处理”它们（添加一个数字，或者看它们是大于还是小于数字）都会出错。

我一直在寻找发生这种情况的情况，我有几个：

ex36.rb:106:in `pirates_room': undefined method `-' for nil:NilClass (NoMethodError)
            from ex36.rb:55:in `start'
            from ex36.rb:143:in `<main>'

ex36.rb:81:in `gold_room': undefined method `+' for nil:NilClass (NoMethodError)
            from ex36.rb:115:in `pirates_room'
            from ex36.rb:55:in `start'
            from ex36.rb:143:in `<main>'

ex36.rb:8:in `score': undefined local variable or method `soul' for main:Object (NameError)
            from ex36.rb:44:in `dead'
            from ex36.rb:59:in `start'
            from ex36.rb:122:in `<main>'

我做错了什么？我没有编码的经验，所以我可能只是做了一些基本的错误，我试图在这里找到答案，但是那个有类似错误的答案似乎不适用于这种情况，或者至少我不喜欢了解它们的应用方式。我不能定义变量然后用方法改变它们吗？

感谢您的帮助。

Ruby：使用方法更改变量时出错

0 个答案: