如何从所需格式的字符串中获取数据，以获得NSData类型

Question

func callAddWithPOST(Name mname:String, PhoneNo mphone:String, Email memail:String, Comment mcomments:String)
{
    var names = [String]()
    let login = ["countryId":"1"]
    print("Your Result is : = \(login)")
    let url = NSURL(string: "http://photokeeper.mgtcloud.co.uk/commonwebservice.asmx/getStateList")!
    let session = NSURLSession.sharedSession()
    let request = NSMutableURLRequest(URL: url)
    do
    {
        let auth = try NSJSONSerialization.dataWithJSONObject(login, options: .PrettyPrinted)
        request.setValue("application/json", forHTTPHeaderField: "Content-Type")
        request.HTTPMethod = "POST"
        request.HTTPBody = auth
        let task = session.dataTaskWithRequest(request, completionHandler: { (data, response, error) -> Void in
            let responseString = String(data:data!, encoding: NSUTF8StringEncoding)
            let validresponseString = "\(responseString!)"
            print(validresponseString)
            let badJsonString = "This really isn't valid JSON at all"
            let jsonData = validresponseString.dataUsingEncoding(NSUTF8StringEncoding)!
            let badJsonData = badJsonString.dataUsingEncoding(NSUTF8StringEncoding)!
            do
            {
                let parsed = try NSJSONSerialization.JSONObjectWithData(jsonData, options: NSJSONReadingOptions.AllowFragments)
                let otherParsed = try NSJSONSerialization.JSONObjectWithData(badJsonData, options: NSJSONReadingOptions.AllowFragments)
            }
            catch let error as NSError
            {
                print("Done.")
            }
        })
        task.resume()
    }
    catch
    {
        print("Error")
    }
}

我正在寻找一种从此方法中获取所需数据的解决方案，我想从此字符串数据中显示StateID和StateName。我无法将NSData中的字符串“responseString”转换为将此字符串作为NSData来获取所需的记录。请问有谁帮我解决这个问题。

Answer 1

如果你想从json获取key的值，你应该使用以下代码将json转换为Dictionary：

Swift 3

JSONSerialization.jsonObject(with: data, options: []) as? [String:AnyObject]

Swift 2

NSJSONSerialization.JSONObjectWithData(data, options: []) as? [String:AnyObject]

如果我在downvote之前误解了某些内容，请在评论中告诉我，谢谢。