每次我通过下面的代码提交表单时,我都会收到“查询失败”,但我似乎无法找到错误。
您的SQL语法中有错误;检查手册 对应于您的MySQL服务器版本,以便使用正确的语法 靠近'order(pass,phone,fname,lname) VALUES('test@yahoo.com','060606060606','James''在第1行
请有人帮帮我。
<?php
//Start session
session_start();
//Include database connection details
require_once('../db/config.php');
//Array to store validation errors
$errmsg_arr = array();
//Validation error flag
$errflag = false;
//Connect to mysql server
$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
if(!$link) {
die('Failed to connect to server: ' . mysql_error());
}
//Select database
$db = mysql_select_db(DB_DATABASE);
if(!$db) {
die("Unable to select database");
}
//Function to sanitize values received from the form. Prevents SQL injection
function clean($str) {
$str = @trim($str);
if(get_magic_quotes_gpc()) {
$str = stripslashes($str);
}
return mysql_real_escape_string($str);
}
//Sanitize the POST values
$pass = clean($_POST['pass']);
$phone = clean($_POST['phone']);
$fname = clean($_POST['fname']);
$lname = clean($_POST['lname']);
//Create INSERT query
$qry = "INSERT INTO order (pass, phone, fname, lname) VALUES('$pass','$phone','$fname','$lname')";
$result = @mysql_query($qry);
//Check whether the query was successful or not
if($result) {
header("location: success.php");
exit();
}else {
die("Query failed");
}
?>
我还试图检查用户输入是否为空且没有问题但是没有插入。
答案 0 :(得分:3)
名称&#39;命令&#39;是MySQL保留的关键字。
使用反引号括起表名
$qry = "INSERT INTO `order` (pass, phone, fname, lname) VALUES('$pass','$phone','$fname','$lname')";
^ enlcose table name with backtick
<强> BACKTICK 强>
答案 1 :(得分:0)
使用&#34; mysqli&#34;
$qry = "INSERT INTO `order` (pass, phone, fname, lname) VALUES('$pass','$phone','$fname','$lname')";
$result = mysqli_query($conn,$qry);