我已尝试使用此公式转换我的数据框中提到的年份＆＃34; Yr＆＃34;成2位数值
yr <- format((Yr[,]), format = "%y")
注意：Yr是一个data.frame，由年值组成。 2015年，2012年，1998年等。我试图将这些值分别加载到变量yr中，格式分别为15,12,98。
答案 0 :(得分：3)
function playbackRecording(content) {
var waitTime = 0;
var keypress = content[0];
actionApp(keypress.key_pressed);
for (var i = 1; i < content.length; i++) {
waitTime += keypress.time_to_next_key;
keypress = content[i];
var end = Date.now() + waitTime;
while(Date.now() < end) {}
actionApp(keypress.key_pressed);
}
}
function playbackLinkClicked(evt) {
var urlString = '/fetch_recording/' + this.id;
$.get(urlString, function(data){
if (data.status === 'success') {
playbackRecording(data.content);
} else {
alert('Could not load recording.');
}
});
}
$('.playback').click(playbackLinkClicked);
怎么样？
echo 'PR-1769|7bb12d4152a497cef491e0a1088b3984ad92972f|jaga|'|awk -F'|' '{print substr($1, 4)}'
另一种方法是使用sprintf("%02d", Year %% 100)，由@alistaire评论：
Year <- 1960:2016
sprintf("%02d", Year %% 100)
# [1] "60" "61" "62" "63" "64" "65" "66" "67" "68" "69" "70" "71" "72" "73" "74"
#[16] "75" "76" "77" "78" "79" "80" "81" "82" "83" "84" "85" "86" "87" "88" "89"
#[31] "90" "91" "92" "93" "94" "95" "96" "97" "98" "99" "00" "01" "02" "03" "04"
#[46] "05" "06" "07" "08" "09" "10" "11" "12" "13" "14" "15" "16"