Question

我有sql查询的php代码

count

此代码在浏览器上打印我的数据库名称如何将数据库名称保存到文本文件

<?
$server = "127.0.0.1";
$username = "root";
$password = "1";

$link= connecttodb($server,$username,$password);

function connecttodb($server,$username,$password)
{

    $rez=fopen("test.txt","ab");
    if ($link=mysql_connect ("$server","$username","$password",TRUE))
    {
        fwrite($rez,"".$server." \r\n");
	    echo "Connected successfully to >> " .$server ;
		
		$result = mysql_query('SHOW DATABASES');
        echo "<br>";
        while ($row = mysql_fetch_array($result))
        {
            var_dump ($row); }
	    }
    }
    ini_set('max_execution_time', 10);
    return $link;
?>

Answer 1

您可以使用输出缓冲功能捕获输出并将其写入文件。

ob_flush();
ob_start();
while ($row = mysql_fetch_assoc($result)) {
    var_dump($row);
}
file_put_contents("dump.txt", ob_get_flush());

Answer 2

不要为此使用var_dump，请使用序列化，如下所示：

<?php
$fp = fopen('vardump.txt', 'w');
fwrite($fp, serialize($myobj));
fclose($fp);
?>

要恢复它，可以使用unserialize（$ filecontents）;通过从文件中读回来。

Answer 3

<?
$server = "127.0.0.1";
$username = "root";
$password = "1";

$link= connecttodb($server,$username,$password);

function connecttodb($server,$username,$password)
{

$rez=fopen("test.txt","ab");
   if ($link=mysql_connect ("$server","$username","$password",TRUE))
   {
   fwrite($rez,"".$server." \r\n");
    echo "Connected successfully to >> " .$server ;

        $result = mysql_query('SHOW DATABASES');
echo "<br>";
while ($row = mysql_fetch_array($result))
{
fwrite($rez, $row['DatabaseName']); }

    }

}
ini_set('max_execution_time', 10);
return $link;
    ?>

Answer 4

这应该有效

$file = 'somefile.txt';
file_put_contents($file, $some_var);

您可能希望首先序列化变量以使其更具可读性。

但还有其他几种方法：http://php.net/manual/en/function.file-put-contents.php

将var_dump保存到文本文件中

4 个答案: