Question

我想在页面加载时显示来自我的数据库的数据，但我不知道如何，我没有找到任何功能方式。插入工作正常。

这是我的数据插入HTML代码：

<html>
  <head>
  <meta http-equiv="content-type" content="text/html; charset=utf-8">
  <meta name="generator" content="PSPad editor, www.pspad.com">
  <title></title>
  </head>
  <body>
     <form action="insert.php" method="post">
      <p>
          <label for="snapname">Name:</label>
          <input type="text" name="snapname">
      </p>
      <p>
          <label for="age">Age:</label>
          <input type="text" name="age">
      </p>
      <input type="submit" value="odeslat">
      </form>
  </body>
</html>

PHP用于连接并将数据插入数据库：

<?php
$servername = "localhost";
$username = "admin";
$password = "***";
$dbname = "db1";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Could not connect to server: " . $conn->connect_error);
} 
$first_name = mysqli_real_escape_string($conn, $_POST['snapname']);
$last_name = mysqli_real_escape_string($conn, $_POST['age']);

$Jmeno = $_POST['snapname'];
$Vek = $_POST['age'];

$sql = "INSERT INTO snapy (ID, username, age, date)
VALUES (0, '$Jmeno', '$Vek', CURRENT_TIMESTAMP)";

if ($conn->query($sql) === TRUE) {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>" . $conn->error;
}

$conn->close();
?>

有人可以帮我在HTML文件中显示数据吗？

Answer 1

您需要运行SELECT请求。由于您使用的是MySQLi，因此您希望使用以下内容：

$sql = "SELECT * FROM snapy";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {
        echo "id: " . $row["id"]. " - Name: " . $row["username"]. " " . $row["age"]. " yo<br>";
    }
} else {
    echo "0 results";
}

在此处找到：http://www.w3schools.com/php/php_mysql_select.asp

在HTML页面中显示数据库中的数据

1 个答案: