JPA CriteriaBuilder中的CollectionAttribute测试

时间:2010-10-08 16:21:52

标签: jpa eclipselink metamodel

我有一个CriteriaBuilder,我正在尝试创建一个谓词来限制CollectionAttribute中的结果。我想说一下像获取实体的属性A等于x的集合中的所有实体。例如,我有很多人物实体。他们有一系列职位(以前和现在),我想知道所有拥有“银行家”头衔的人。这是一个例子:

CriteriaBuilder builder = em.getCriteriaBuilder();
CriteriaQuery<Object> query = builder.createQuery();
Root<MheAreaLocation> root = query.from(MheAreaLocation.class);

Predicate p2 = builder.equal(root.get(Jobs_.jobs).get(Jobs_.titles), "banker");

TypedQuery<Object> q = em.createQuery(query);
List<Object> resultList = q.getResultList();
...

任何帮助都会很棒。我正在努力找到很多关于CollectionAttribute并在谓词中使用它们...当我在谓词中使用下面的连接时,我一直得到空值:-(谢谢

这是我的实际代码:

CriteriaBuilder builder = em.getCriteriaBuilder();
// CriteriaQuery<Tuple> query = builder.createQuery();
CriteriaQuery<Object> query = builder.createQuery();
Root<MheAreaLocation> mheAreaLocationRoot = query.from(MheAreaLocation.class);

CollectionJoin<MheLocation, AtlasLocationGroupMap> join = mheAreaLocationRoot.join(MheAreaLocation_.childLocation).join(MheLocation_.atlasLocationGroupMapCollection);
// .join(AtlasLocationGroupMap_.atlasLocationGroup, JoinType.INNER);

Predicate p1 = builder.equal(mheAreaLocationRoot.get(MheAreaLocation_.parentLocation).get(MheLocation_.mheLocId), "AZP1B");
// Predicate p2 = builder.equal(mheAreaLocationRoot.get(MheAreaLocation_.childLocation).get(MheLocation_.atlasLocationGroupMapCollection).);
Predicate p2 = builder.equal(join.get(AtlasLocationGroupMap_.atlasLocationGroup).get(AtlasLocationGroup_.locationGroupType), "NEXT_STATION");

// query.where(builder.and(e1, e2));

// mheAreaLocationRoot.fetch(MheAreaLocation_.childLocation);
// join.fetch(MheLocation_.atlasLocationGroupMapCollection);

// query.multiselect(mheAreaLocationRoot.get(MheAreaLocation_.parentLocation),
// mheAreaLocationRoot.get(MheAreaLocation_.childLocation));
// query.select(builder.tuple(join.get(AtlasLocationGroupMap_.mheLocation)));

TypedQuery<Object> q = em.createQuery(query);
List<Object> resultList = q.getResultList();
...

其他课程(如果需要,我可以添加更多):

@StaticMetamodel(MheLocation.class)
public class MheLocation_ { 
   public static volatile CollectionAttribute<MheLocation, AtlasLocationGroupMap> atlasLocationGroupMapCollection;
   public static volatile SingularAttribute<MheLocation, String> mheLocId;
}

2 个答案:

答案 0 :(得分:0)

以此示例为例,其中包含Farm和Animal类(Farm有一个集合&lt; Animal&gt;),我们想对Animal的名称强加一个标准。与我的想法不完全相同,但可能会指出正确的方向

CriteriaBuilder qb = emf.getCriteriaBuilder();
CriteriaQuery<Farm> crit = qb.createQuery(Farm.class);
Root<Farm> candidate = crit.from(Farm.class);
candidate.alias("f");
crit.select(candidate);

Metamodel model = emf.getMetamodel();
ManagedType farmType = model.managedType(Farm.class);
Attribute animalAttr = farmType.getAttribute("animals");
Join animalJoin = candidate.join((ListAttribute)animalAttr);
animalJoin.alias("a");

Path nameField = animalJoin.get("name");
Predicate nameEquals = qb.equal(nameField, "Woolly Sheep");
crit.where(nameEquals);

等于 SELECT f FROM org.jpox.samples.annotations.one_many.bidir.Farm f JOIN f.animals a WHERE (a.name = 'Woolly Sheep')

HTH

答案 1 :(得分:0)

您可以使用CollectionJoin来解决此问题。查看CollectionJoin example in JPA Criteria