Question

我在我的网站上使用旧的MySql版本和php版本4的Oscommeerce。

我的表结构：

| orders_status_history_id |  orders_id |  orders_status_id |
|            1             |      22    |         3         |
|            2             |      23    |         2         |
|            3             |      24    |         5         |
|            4             |      75    |         5         |
|            5             |      25    |         5         |
|            6             |      30    |         1         |
|            7             |      26    |         2         |
|            8             |      75    |         54        |
|            10            |      22    |         5         |
|            15            |      48    |         6         |
|            16            |      52    |         8         |
|            17            |      32    |         9         |
|            18            |      75    |         54        |
|            19            |      24    |         5         |
|            22            |      20    |         8         |
|            23            |      75    |         54        |
|            ..            |      ..    |         ..        |
|            ..            |      ..    |         ..        |

我的表总共超过2000000行。

orders_status_history_id列为auto increment。

所以我的问题是：

我如何获得orders_id orders_status_id有两次54 id的位置？

对于examaple：如果orders_id 75 orders_status_id = 54，那么它应该显示orders_id 75，如果没有，则跳过它。

所以我希望输出如此：

|     orders_status_id     |  orders_id | 
|            54            |      75    |

我厌倦了以下方式：

$sql = "SELECT 
            orders_status_history_id, orders_id, orders_status_id 
        FROM 
            orders_status_history 
        Where 
            (orders_status_history_id > ".$dal." AND orders_status_history_id < ".$al.") 
        AND 
            orders_id IN(
                    Select Distinct
                        orders_id
                    From 
                        orders_status_history 
                    Where  
                        (orders_status_history_id > ".$dal." AND orders_status_history_id < ".$al.")
                    HAVING
                        count(orders_status_id=54)>2
                )";

没用？

SELECT 
    orders_status_history_id, orders_id, orders_status_id 
    FROM 
        orders_status_history 
    WHERE 
        (orders_status_history_id > 0 AND orders_status_history_id < 500)
    AND
        orders_id IN (
            Select 
                orders_id 
            FROM 
                orders_status_history 
            WHERE
                (orders_status_history_id > 0 AND orders_status_history_id < 1000)
            AND  
                count(orders_status_id=54) >2
        )

我找不到查询来获取所需的结果。

我究竟做错了什么？

提前致谢。

Answer 1

我会使用group by和having：

执行此操作

select orders_id
from orders_status_history
where orders_status_id = 54
group by orders_id
having count(*) >= 2;

如果您确实需要完整的详细信息，请使用join或in：

select osh.*
from orders_status_history osh join
     (select orders_id
      from orders_status_history
      where orders_status_id = 54
      group by orders_id
      having count(*) >= 2
     ) o
     on osh.orders_id = o.orders_id;

Answer 2

试试这个：

SELECT orders_status_history_id, orders_id, orders_status_id
FROM orders_status_history
WHERE (orders_status_history_id > 0 AND orders_status_history_id < 500) and orders_id IN (
    SELECT orders_id
    FROM orders_status_history
    GROUP BY orders_id
    HAVING COUNT(orders_status_history_id) > 1
)

Answer 3

喜欢这个吗？

SELECT orders_id, orders_status_id
FROM test
AS r
WHERE (
    SELECT count(*) FROM test
    WHERE orders_id=r.orders_id AND orders_status_id=r.orders_status_id
)>=2
GROUP BY orders_status_id

希望有效。

获取order_id，其中order_id有两个时间x值

3 个答案: