一切运行良好但是当我插入一条记录并尝试编辑相同的记录时,它将不会被编辑并编辑相同的记录我必须刷新页面,同样的情况发生在更新中,一旦记录更新,我必须刷新编辑同一记录的页面
<html ng-app="crudApp">
<head>
<meta charset="UTF-8">
<title>Angular js</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/angularjs/1.0.7/angular.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
</head>
<body ng-controller="DbController">
<form id="form" name="employee">
First Name: <input type="text" ng-model="firstname"><br/><br/>
Last Name: <input type="text" ng-model="lastname"><br/><br/>
<input type="submit" name="btnInsert" id="Insert" value="Insert" ng-click='insertData()'/>
<input type="submit" name="btnUpdate" id="Update"value="Update" ng-click='UpdateData(currentUser)'/>
</form>
<div>
<table border="1">
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Delete</th>
<th>Edit</th>
</tr>
<tr ng-repeat="detail in details">
<td>{{detail.firstname}}</td>
<td>{{detail.lastname}}</td>
<td><input type="button" value="Delete" ng-click="deleteInfo(detail.id)"/></td>
<td><input type="button" value="Edit" ng-click="editInfo(detail.id)"/></td>
</tr>
</table>
</div>
<script>
var crudApp = angular.module('crudApp', []);
crudApp.controller("DbController", ['$scope', '$http', function ($scope, $http) {
getInfo();
function getInfo() {
$http.post('select.php').success(function (data) {
// Stored the returned data into scope
$scope.details = data;
});
}
$scope.deleteInfo = function (info) {
$http.post('delete.php', {del_id: info
}).success(function (result) {
getInfo()
console.log(result);
});
}
$scope.insertData = function () {
$http.post("insert.php", {
'firstname': $scope.firstname,
'lastname': $scope.lastname,
}).success(function () {
getInfo();
document.getElementById("form").reset();
});
}
$scope.editInfo = function (info) {
$scope.currentUser = info;
$http.post('edit.php', {edit_id: $scope.currentUser,
}).success(function (result) {
$scope.firstname = result[0]['firstname'],
$scope.lastname = result[0]['lastname'],
$("#Insert").hide();
$("#Update").show();
});
}
$scope.UpdateData = function (currentUser) {
$http.post("update.php", {
'firstname': $scope.firstname,
'lastname': $scope.lastname,
'update_id': currentUser,
}).success(function (result) {
getInfo();
$("#Insert").show();
$("#Update").hide();
document.getElementById("form").reset();
});
}
}]);
</script>
</body>
</html>
答案 0 :(得分:2)
编辑完成后,您将响应数据插入新变量中。这不应该发生。您应该仅更新旧数据(即$scope.detail
)。
以下是:
首先,在您的<table>
代码中,您必须再传递1个参数,即$index
。这个$index
是我们必须更新的记录的关键。我们需要它来更新$scope.detail
的记录。
<table border="1">
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Delete</th>
<th>Edit</th>
</tr>
<tr ng-repeat="detail in details">
<td>{{detail.firstname}}</td>
<td>{{detail.lastname}}</td>
<td><input type="button" value="Delete" ng-click="deleteInfo(detail.id)"/></td>
<td><input type="button" value="Edit" ng-click="editInfo(detail.id, $index)"/></td>
</tr>
</table>
其次,请参阅editInfo()
的此代码。而不是将响应数据分配给新变量。我们仅从$scope.detail
更新旧数据。了解我们如何使用我们从上一步获得的index
变量找到我们的数据。
//info: this info is the detail.id that you've passed from the table
//index: this is the index of the record from $scope.detail that we want want to edit.
$scope.editInfo = function (info, index) {
$scope.currentUser = info;
$http.post('edit.php', {edit_id: $scope.currentUser,
}).success(function (result) {
$scope.detail[index] = result[0]['firstname'];
$scope.detail[index] = result[0]['lastname'];
$("#Insert").hide();
$("#Update").show();
});
}