有一个动态LINQ扩展程序库已作为样本Visual Studio 2008发布。我想用join方法扩展它。下面的代码在运行时失败并带有参数未匹配异常。问题在哪里?
public static IQueryable Join(this IQueryable outer, IEnumerable inner,
string outerSelector, string innerSelector, string resultsSelector,
params object[] values)
{
if (inner == null)
throw new ArgumentNullException("inner");
if (outerSelector == null)
throw new ArgumentNullException("outerSelector");
if (innerSelector == null)
throw new ArgumentNullException("innerSelector");
if (resultsSelector == null)
throw new ArgumentNullException("resultsSelctor");
LambdaExpression outerSelectorLambda =
DynamicExpression.ParseLambda(outer.ElementType, null,
outerSelector, values);
LambdaExpression innerSelectorLambda =
DynamicExpression.ParseLambda(inner.AsQueryable().ElementType,
null, innerSelector, values);
ParameterExpression[] parameters = new ParameterExpression[] {
Expression.Parameter(outer.ElementType, "outer"),
Expression.Parameter(inner.AsQueryable().ElementType,
"inner")
};
LambdaExpression resultsSelectorLambda =
DynamicExpression.ParseLambda(parameters, null,
resultsSelector, values);
return outer.Provider.CreateQuery(
Expression.Call(
typeof(Queryable), "Join", new Type[] {
outer.ElementType,
inner.AsQueryable().ElementType,
outerSelectorLambda.Body.Type,
innerSelectorLambda.Body.Type,
resultsSelectorLambda.Body.Type
},
outer.Expression, inner.AsQueryable().Expression,
Expression.Quote(outerSelectorLambda),
Expression.Quote(innerSelectorLambda),
Expression.Quote(resultsSelectorLambda))
);
}
答案 0 :(得分:24)
我现在已经修好了。这是一个小学生错误,将过多的参数传递给CreateQuery(...)调用。将以下代码粘贴到DynamicQueryable类中的Dynamic.cs文件中,以获取动态Join扩展方法。您可以在http://code.msdn.microsoft.com/csharpsamples找到DynamicQuery示例项目的源代码。
享受。
public static IQueryable Join(this IQueryable outer, IEnumerable inner, string outerSelector, string innerSelector, string resultsSelector, params object[] values)
{
if (inner == null) throw new ArgumentNullException("inner");
if (outerSelector == null) throw new ArgumentNullException("outerSelector");
if (innerSelector == null) throw new ArgumentNullException("innerSelector");
if (resultsSelector == null) throw new ArgumentNullException("resultsSelctor");
LambdaExpression outerSelectorLambda = DynamicExpression.ParseLambda(outer.ElementType, null, outerSelector, values);
LambdaExpression innerSelectorLambda = DynamicExpression.ParseLambda(inner.AsQueryable().ElementType, null, innerSelector, values);
ParameterExpression[] parameters = new ParameterExpression[] {
Expression.Parameter(outer.ElementType, "outer"), Expression.Parameter(inner.AsQueryable().ElementType, "inner") };
LambdaExpression resultsSelectorLambda = DynamicExpression.ParseLambda(parameters, null, resultsSelector, values);
return outer.Provider.CreateQuery(
Expression.Call(
typeof(Queryable), "Join",
new Type[] {outer.ElementType, inner.AsQueryable().ElementType, outerSelectorLambda.Body.Type, resultsSelectorLambda.Body.Type },
outer.Expression, inner.AsQueryable().Expression, Expression.Quote(outerSelectorLambda), Expression.Quote(innerSelectorLambda), Expression.Quote(resultsSelectorLambda)));
}
//The generic overload.
public static IQueryable<T> Join<T>(this IQueryable<T> outer, IEnumerable<T> inner, string outerSelector, string innerSelector, string resultsSelector, params object[] values)
{
return (IQueryable<T>)Join((IQueryable)outer, (IEnumerable)inner, outerSelector, innerSelector, resultsSelector, values);
}
答案 1 :(得分:3)
您可以安装System.Linq.Dynamic.Core的nuget包 - https://github.com/StefH/System.Linq.Dynamic.Core
这个连接方法与各种其他辅助方法一起实现。
使用此库,您可以按照以下方式进行简单连接
myContext.TableA.Join(myContext.TableB,'Id','TableAId','outer',null)
outer
中的和inner
是访问连接结果的关键字。
使用具有多个属性的键和/或选择具有多个属性的结果可以通过以下方式完成
myContext.TableA.Join(myContext.TableB,'new (Id as key1,Code as key2)','new (TableAId as key1,AnotherCol as key2)','new(outer.Id,inner.Desc)',null)
答案 2 :(得分:1)
以下是一些显示多列连接的示例代码。使用数据表和数据行,您需要始终通过索引器访问字段。
DataTable t1 = new DataTable();
t1.Columns.Add("FundId", typeof(int));
t1.Columns.Add("Date", typeof(DateTime));
t1.Columns.Add("CodeA", typeof(string));
t1.Rows.Add(1, new DateTime(2010, 01, 01), "A1");
t1.Rows.Add(2, new DateTime(2010, 01, 01), "A2");
t1.Rows.Add(3, new DateTime(2010, 01, 01), "A3");
DataTable t2 = new DataTable();
t2.Columns.Add("FundId", typeof(int));
t2.Columns.Add("Date", typeof(DateTime));
t2.Columns.Add("CodeB", typeof(string));
t2.Rows.Add(1, new DateTime(2010, 01, 01), "B1");
t2.Rows.Add(2, new DateTime(2010, 01, 01), "B2");
t2.Rows.Add(3, new DateTime(2010, 01, 01), "B3");
IQueryable outerTable = t1.AsEnumerable().AsQueryable();
IEnumerable innerTable = t2.AsEnumerable();
var query = outerTable.Join
(
innerTable,
"new(get_Item(0) as FundId, get_Item(1) as Date)",
"new(get_Item(0) as FundId, get_Item(1) as Date)",
"new(outer.get_Item(0) as FundId, outer.get_Item(2) as CodeA, inner.get_Item(2) as CodeB)"
);