Python多处理 - 如何将kwargs传递给函数?

时间:2016-08-12 01:54:33

标签: python multiprocessing kwargs

如何使用Python的多处理将字典传递给函数?文档:https://docs.python.org/3.4/library/multiprocessing.html#reference说要传递字典,但我一直在

TypeError: fp() got multiple values for argument 'what'

以下是代码:

from multiprocessing import Pool, Process, Manager

def fp(name, numList=None, what='no'):
        print ('hello %s %s'% (name, what))
        numList.append(name+'44')

if __name__ == '__main__':

    manager = Manager()

    numList = manager.list()
    for i in range(10):
        keywords = {'what':'yes'}
        p = Process(target=fp, args=('bob'+str(i)), kwargs={'what':'yes'})
        p.start()
        print("Start done")
        p.join()
        print("Join done")
    print (numList)

1 个答案:

答案 0 :(得分:13)

当我运行你的代码时,我得到了一个不同的错误:

TypeError: fp() takes at most 3 arguments (5 given)

我通过打印args和kwargs并将方法更改为fp(*args, **kwargs)来调试,并注意到" bob _"被传递为一系列字母。似乎用于args的括号是可操作的,实际上并没有给你一个元组。将它更改为列表,然后传递numList作为关键字参数,使代码适合我。

from multiprocessing import Pool, Process, Manager

def fp(name, numList=None, what='no'):
    print ('hello %s %s' % (name, what))
    numList.append(name+'44')

if __name__ == '__main__':

    manager = Manager()

    numList = manager.list()
    for i in range(10):
        keywords = {'what': 'yes', 'numList': numList}
        p = Process(target=fp, args=['bob'+str(i)], kwargs=keywords)
        p.start()
        print("Start done")
        p.join()
        print("Join done")
    print (numList)