Java ArrayList包含()方法不起作用

时间:2016-08-11 16:44:43

标签: java android sorting wireless

我毫不怀疑contains()方法工作正常,但显然我做错了。我正在开发一个Android应用程序,我正在检测WiFi并在listView中列出WiFi。我试图过滤掉同一个访问点的重复出现,所以我创建一个数组来跟踪重复项。这是我的代码:

function doSomething(){
  ... execute code here ...
}

// Invoke function
doSomething();

这是apList项的内容或我调用apList.get(i)时得到的内容:

public void getWifi(){

    ListView wifiList = (ListView)findViewById(R.id.listView);

    WifiManager wifiManager = (WifiManager) getSystemService(Context.WIFI_SERVICE);
    List<ScanResult> apList = wifiManager.getScanResults();
    wifiManager.startScan();

    List<String> wifees = new ArrayList<>();

    //split info into arrays
    for(int i=0; i < apList.size(); i++){

        String[] daList = String.valueOf(apList.get(i)).split(",");

        String info = "";
        List<String> SSIDs = new ArrayList<>();

        for (String listItem : daList) {
            String topic = String.valueOf(listItem.split(":")[0]);
            String val = listItem.split(":")[1];
            Log.d(TAG, topic);
            if (Objects.equals(topic, "SSID")) {
                if(SSIDs.contains(val)){
                    Log.d(TAG, "CONTAINS");
                    break;
                } else {
                    SSIDs.add(val);
                    info = val;
                }
            } else if (Objects.equals(topic, " level")){
                String strength = "";
                if (Integer.parseInt(val.substring(1)) >= -35) {
                    strength = "100%";
                } else if (Integer.parseInt(val.substring(1)) <= -35 && Integer.parseInt(val.substring(1)) >= -65) {
                    strength = "50%";
                } else {
                    strength = "1%";
                }
                info += "   " + strength;
            }
        }
        wifees.add(info);
    }

    assert wifiList != null;
    ArrayAdapter apter = new ArrayAdapter(this, android.R.layout.simple_list_item_1, wifees);
    wifiList.setAdapter(apter);
}

以下是该代码的输出(大致是因为它是在手机上,出于安全原因我宁愿不包括AP名称):

SSID: SCHOOL-GUEST, BSSID: 04:04:04:04:04:04, capabilities: [ESS], level: -91, frequency: 2412, timestamp: 72500687089, distance: ?(cm), distanceSd: ?(cm), passpoint: no, ChannelBandwidth: 0, centerFreq0: 0, centerFreq1: 0, 80211mcResponder: is not supported

如果我能得到第二个意见,那就太好了。我觉得我错过了一些明显的东西。谢谢!

1 个答案:

答案 0 :(得分:2)

.contains无效,因为您在List<String> SSIDs = new ArrayList<>();内致电for(int i=0; i < apList.size(); i++){。您基本上为每个循环迭代创建新的空List。你应该在外部for循环中调用它一次:

List<String> SSIDs = new ArrayList<>();
for(int i=0; i < apList.size(); i++){
    ...
}