我正在开发一个带有故事板的OS X应用程序。我在带有自定义ViewController的匿名窗口上使用入口点获得Preview.storyboard。在AppDelegate类中,我得到以下函数。
func newPreviewWindow(sender: AnyObject) {
let storyboard = NSStoryboard.init(name: "Preview", bundle: nil)
let initialController = storyboard.instantiateInitialController()
initialController!.showWindow(nil)
initialController!.makeKeyAndOrderFront(nil)
}
运行代码时,窗口显示,但我得到以下异常:
2016-08-11 10:27:12.434 MyApp[1090:290439] -[NSWindowController makeKeyAndOrderFront:]: unrecognized selector sent to instance 0x60000008c350
2016-08-11 10:27:12.434 MyApp[1090:290439] -[NSWindowController makeKeyAndOrderFront:]: unrecognized selector sent to instance 0x60000008c350
2016-08-11 10:27:12.440 MyApp[1090:290439] (
0 CoreFoundation 0x00007fff926284f2 __exceptionPreprocess + 178
1 libobjc.A.dylib 0x00007fff97c0ef7e objc_exception_throw + 48
2 CoreFoundation 0x00007fff926921ad -[NSObject(NSObject) doesNotRecognizeSelector:] + 205
3 CoreFoundation 0x00007fff92598571 ___forwarding___ + 1009
4 CoreFoundation 0x00007fff925980f8 _CF_forwarding_prep_0 + 120
5 MyApp 0x0000000100005617
...
基于异常消息并在Google和StackOverflow上搜索,我尝试以这种方式向makeKeyAndOrderFront
函数发送选择器:
func newPreviewWindow(sender: AnyObject) {
let storyboard = NSStoryboard.init(name: "Preview", bundle: nil)
let initialController = storyboard.instantiateInitialController()
let selector = #selector(AppDelegate.newPreviewWindow(_:))
initialController!.showWindow(nil)
initialController!.makeKeyAndOrderFront(selector) // [A]
}
但是我在[A]行上得到以下编译错误:Cannot call value of non-function type '((AnyObject?) -> Void)!'
打开新窗口或传递选择器的正确方法如何?
谢谢! :)
答案 0 :(得分:1)
df$gap <- c(0, (diff(df$date) > 1)*1) # identify gap between dates larger than 1
df$group <- cumsum(df$gap) + 1 # cumulative sum of 'gap' variable
导致问题,因为initialController!.makeKeyAndOrderFront(nil)
不是makeKeyAndOrderFront:
方法 - 它属于NSWindowController
(因此无法识别的选择器错误) 。将初始控制器转换为NSWindow
子类,然后通过控制器的NSWindowController
属性将窗口置于前面:
window