Question

我有两张桌子，

table1有两列：

id(PK)     |   sentence(varchar 255)
1          |   I am a boy; a good boy.

和table2有两列：

word    |   meaning
I       |     مين
am      |     هون
a       |     أيك 
boy     |     لرقة 
good    |     اشا

现在我想以这样的方式查询（仅使用MySQL的单个查询）这两个表格，我将通过其翻译获得每个单词。

对于样本数据，查询结果必须为：

sentence                  |    word_meaning (virtual column)
I am a boy; a good boy.   |  {"I":"مين", "am":"هون", "a":"أيك", "boy":"لرقة", "good":"اشا"}

正如您在word_meaning列中所看到的，每个单词都与json有关。

Answer 1

这是一个简化的答案。您需要准备句子-用空格更改所有非单词符号。比较时，该查询将使用UPPER忽略字符大小写。

创建和填写表格：

CREATE TABLE table1(id int auto_increment primary key, sentence varchar(250));
CREATE TABLE table2(word varchar(120), meaning varchar(120));
INSERT INTO table1(sentence) VALUES ("This is a test sentence"), ("This is another sentence");
INSERT INTO table2 VALUES ("This", "used to identify a specific person or thing"), ("is", "auxiliary verb"), ("test", "a procedure intended to establish the quality, performance, or reliability of something"), ("sentence", "a set of words that is complete in itself");

查询：

SELECT prepared.id, prepared.idx, prepared.word, IFNULL(table2.meaning, "!!! NO TRANSLATION FOUND")
FROM
    (SELECT
        id,
        idx,
        SUBSTRING_INDEX(SUBSTRING_INDEX(sentence, ' ', idx), ' ', -1) word
    FROM
        table1
    JOIN 
        (SELECT t1.idx * 10 + t2.idx + 1 idx FROM (
            (SELECT 0 idx UNION ALL SELECT 1 idx UNION ALL SELECT 2 idx UNION ALL SELECT 3 idx UNION ALL SELECT 4 idx UNION ALL SELECT 5 idx UNION ALL SELECT 6 idx UNION ALL SELECT 7 idx UNION ALL SELECT 8 idx UNION ALL SELECT 9 idx) t1
            CROSS JOIN
            (SELECT 0 idx UNION ALL SELECT 1 idx UNION ALL SELECT 2 idx UNION ALL SELECT 3 idx UNION ALL SELECT 4 idx UNION ALL SELECT 5 idx UNION ALL SELECT 6 idx UNION ALL SELECT 7 idx UNION ALL SELECT 8 idx UNION ALL SELECT 9 idx) t2
        )) idx on idx.idx - 2 < LENGTH(sentence) - LENGTH(REPLACE(sentence, " ", ""))) prepared
LEFT JOIN
    table2 on UPPER(table2.word) = UPPER(prepared.word)
ORDER BY prepared.id, prepared.idx;

这将产生：

1   1   This        used to identify a specific person or thing
1   2   is          auxiliary verb
1   3   a           !!! NO TRANSLATION FOUND
1   4   test        a procedure intended to establish the quality, performance, or reliability of something
1   5   sentence    a set of words that is complete in itself
2   1   This        used to identify a specific person or thing
2   2   is          auxiliary verb
2   3   another     !!! NO TRANSLATION FOUND
2   4   sentence    a set of words that is complete in itself

请注意，这只是一个示例。索引的使用可以帮助提高性能。

要获取一些JSON数组：

SELECT 
    JSON_ARRAY(
        group_concat(JSON_OBJECT("sentecne_id", id, "word_idx", idx, "word", word, "meaning", meaning)),
        "]"
    ) result
FROM (
    SELECT prepared.id, prepared.idx, prepared.word, IFNULL(table2.meaning, "!!! NO TRANSLATION FOUND") meaning
    FROM
        (SELECT
            id,
            idx,
            SUBSTRING_INDEX(SUBSTRING_INDEX(sentence, ' ', idx), ' ', -1) word
        FROM
            table1
        JOIN 
            (SELECT t1.idx * 10 + t2.idx + 1 idx FROM (
                (SELECT 0 idx UNION ALL SELECT 1 idx UNION ALL SELECT 2 idx UNION ALL SELECT 3 idx UNION ALL SELECT 4 idx UNION ALL SELECT 5 idx UNION ALL SELECT 6 idx UNION ALL SELECT 7 idx UNION ALL SELECT 8 idx UNION ALL SELECT 9 idx) t1
                CROSS JOIN
                (SELECT 0 idx UNION ALL SELECT 1 idx UNION ALL SELECT 2 idx UNION ALL SELECT 3 idx UNION ALL SELECT 4 idx UNION ALL SELECT 5 idx UNION ALL SELECT 6 idx UNION ALL SELECT 7 idx UNION ALL SELECT 8 idx UNION ALL SELECT 9 idx) t2
            )) idx on idx.idx - 2 < LENGTH(sentence) - LENGTH(REPLACE(sentence, " ", ""))) prepared
    LEFT JOIN
        table2 on UPPER(table2.word) = UPPER(prepared.word)
    ORDER BY prepared.id, prepared.idx
) translated;

如何匹配两个表

1 个答案: