Question

依据查询显示进出，但结束日期，然后第二天从外面开始。我的表数据是：

attendance_id student_id get_id attendance_date attendancetime create_user create_datetime     edit_user edit_datetime
            1          8      0 2016-08-02      12:10:01                 0 0000-00-00 00:00:00         0 0000-00-00 00:00:00 
            2          8      0 2016-08-02      00:00:00                 0 0000-00-00 00:00:00         0 0000-00-00 00:00:00
            3          8      0 2016-08-02      14:00 00                 0 2016-08-08 05:00:00         0 0000-00-00 00:00:00
            5          8      0 2016-08-06      06:00:00                 0 2016-08-08 05:00:00         0 0000-00-00 00:00:00
            6          8      0 2016-08-06      13:00:00                 0 2016-08-08 05:00:00         0 0000-00-00 00:00:00 
            7          8      0 2016-08-10      06:00:00                 1 2016-08-11 01:58:00         1 2016-08-11 01:58:00 
            8          8      0 2016-08-10      12:00:00                 1 2016-08-11 01:58:00         1 2016-08-11 01:58:00

我的代码是：

$dategroup_str = "SELECT  b.all_date,hostel_attendance.attendancetime,hostel_attendance.attendance_date FROM 
                            (SELECT * FROM 
                            (SELECT ADDDATE('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) all_date FROM 
                            (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t0, 
                            (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t1, 
                            (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t2, 
                            (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t3, 
                            (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t4) 
                            AS d ".$where_clause." ) AS b
                            LEFT JOIN hostel_attendance ON b.all_date = hostel_attendance.attendance_date 
                            AND  hostel_attendance.student_id='$show_student_id' order BY b.all_date";
    echo $dategroup_str;
    $dategroup_sql = $mysqli->query($dategroup_str);
    $dategroup_count = $dategroup_sql->num_rows;
    $i=1;
    $j=0;
    while($dategroup_sel = $dategroup_sql->fetch_row())
    { 
        if($i%2 != 0){?>
        <tr>
            <td class="center" style="text-transform:capitalize;"><?php echo $dategroup_sel[0];?></td>

            <td class="center" style="text-transform:capitalize;">
            <?php if($dategroup_sel[1]!=''){echo $dategroup_sel[1];}else{echo "-";}?>
            </td>
            <?php }elseif($i%2 == 0){?>
            <td class="center" style="text-transform:capitalize;">
            <?php if($dategroup_sel[1]!=''){echo $dategroup_sel[1];}else{echo "-";}?>
            </td>
         </tr>
            <?php }
        $i++; } ?>
        </tbody>
    </table>

输出是我的输出显示此类型

Answer 1

$ datearr_str =＆＃34; SELECT b.all_date，hostel_attendance.attendancetime FROM （SELECT * FROM （选择添加（＆＃39; 1970-01-01＆＃39;，t4.i * 10000 + t3.i * 1000 + t2.i * 100 + t1.i * 10 + t0.i）all_date FROM （SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9）t0，（SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9）t1，（SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9）t2，（SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9）t3，（SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9）t4） AS d＆＃34;。$ where_clause。＆＃34; ）AS b LEFT JOIN hostel_attendance ON b.all_date = hostel_attendance.attendance_date AND hostel_attendance.student_id =＆＃39; $ show_student_id＆＃39;订单BY b.all_date，hostel_attendance.attendancetime＆＃34 ;; // echo $ datearr_str; $ datearr_sql = $ mysqli-＆gt; query（$ datearr_str）; $ datearr_count = $ datearr_sql-＆gt; num_rows; $ datestr =＆＃34;＆＃34 ;; $ timestr =＆＃34;＆＃34 ;; while（$ datearr_sel = $ datearr_sql-＆gt; fetch_row（）） {
if（$ datestr ==＆＃34;＆＃34;）{$ datestr = $ datearr_sel [0];} else {$ datestr = $ datestr。＆＃34;，＆＃34;。$ datearr_sel [0]; } if（$ timestr ==＆＃34;＆＃34;）{$ timestr = $ datearr_sel [1];} else {$ timestr = $ timestr。＆＃34;，＆＃34;。$ datearr_sel [1]; } } $ datearr = explode（＆＃34;，＆＃34;，$ datestr）; $ timearr = explode（＆＃34;，＆＃34;，$ timestr）; //的print_r（$ timearr）; $ dtgp_str =＆＃34; SELECT b.all_date，hostel_attendance.attendancetime，hostel_attendance.attendance_id FROM （SELECT * FROM （选择添加（＆＃39; 1970-01-01＆＃39;，t4.i * 10000 + t3.i * 1000 + t2.i * 100 + t1.i * 10 + t0.i）all_date FROM （SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9）t0，（SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9）t1，（SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9）t2，（SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9）t3，（SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9）t4） AS d＆＃34;。$ where_clause。＆＃34; ）AS b LEFT JOIN hostel_attendance ON b.all_date = hostel_attendance.attendance_date AND hostel_attendance.student_id =＆＃39; $ show_student_id＆＃39;订单BY b.all_date，hostel_attendance.attendancetime＆＃34 ;; // echo $ dtgp_str; $ dtgp_sql = $ mysqli-＆gt; query（$ dtgp_str）; $ dtgp_count = $ dtgp_sql-＆gt; num_rows; $ J = 1; $ K = 1; $升= 1; //的print_r（$ timearr）;

    while($dtgp_sel = $dtgp_sql->fetch_row())
    { 
        $all_date  = $dtgp_sel[0];
        $next_date = $datearr[$l];
        //echo $timearr[$k];
        //echo "k- ".$k;
        if($timearr[$k] !=""){$one_time_before_time = $timearr[$k];}else{$one_time_before_time = '551';}
        if($j !=$l){
            ?>          
                <tr>
                    <td class="center" style="text-transform:capitalize;"><?php echo $all_date;?></td>

                    <td class="center" style="text-transform:capitalize;">
                    <?php if($dtgp_sel[1]!=''){echo $dtgp_sel[1]; }else{echo "-";}?>
                    </td>


                    <?php //echo $all_date . "/". $next_date;
                    if(strtotime($all_date)==strtotime($next_date))
                    { ?>
                        <td class="center" style="text-transform:capitalize;"><?php  echo $one_time_before_time; ?></td> 

                    <?php $i=2; $k=$k+$i;}
                     else
                        {?>
                            <td class="center" style="text-transform:capitalize;"><?php  echo "-" ; ?></td> 
                        <?php $i=1;$k=$k+$i;  } ?>

                 </tr>
                    <?php

            //echo " j-".$j." i-".$i." l-".$l."<br>";   
         $j=$j+$i; }$l++; } ?>
        </tbody>
    </table>
                            </div>

显示进出的询问查询

1 个答案: